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kari74 [83]
3 years ago
10

What is cosmic microwave background radiation?

Physics
1 answer:
chubhunter [2.5K]3 years ago
6 0
Cosmic, or background, radiation is the small amount of high energy radiation which is mostly left over from the big bang or from supernovas. It is mostly single protons, but also alpha particles and even sometimes heavier elements. It can also refer to the low levels of electromagnetic radiation present all over the universe.
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An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train. When the engineer first
GarryVolchara [31]

Answer:

The right answer is "1.369 m/s²".

Explanation:

The given values are:

Distance (s)

= 260 m

Initial speed (u)

= 26 m/s

Reaction time (t')

= 0.51 s

During reaction time, the distance travelled by locomotive will be:

⇒  s'=ut'

        =26\times 0.51

        =13.26 \ m

Remained distance between locomotive and car:

⇒  x=s-s'

         =260-13.26

         =246.74 \ m

Now,

The final velocity to avoid collection is, V = 0 m/s

From third equation of motion:

⇒  V^2=u^2+2ax

On putting the estimated values, we get

⇒  0=(26)^2+2\times a\times 246.74

⇒  0=676+493.48a

⇒  493.48a=-676

⇒            a=-\frac{676}{493.48}

⇒            a=1.369 \ m/s^2

3 0
3 years ago
A 2.69-kg drone is flying over a lake. With both the x and y directions horizontal (that is, viewing the drone from above), the
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A set of statements that belong together as a group and contribute to the function definition is known as a(n) ________.
dsp73
Block. hope this helps.
5 0
3 years ago
The question is on the picture
Firlakuza [10]

Answer:

<em> think 2 also if not im so sorry  but i think it is :)</em>

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2 years ago
Give two mathematical examples of Newton's third law and how you get the solution​
bagirrra123 [75]

Answer:

1) Any particle moving in a horizontal plane slowed by friction, deceleration = 32 μ

2) The particle moving by acceleration = P/m - 32μ OR The external force = ma + 32μm

Explanation:

* Lets revise Newton’s Third Law:

- For every action there is a reaction, equal in magnitude and opposite

 in direction.

- Examples:

# 1) A particle moving freely against friction in a horizontal plane

- When no external forces acts on the particle, then its equation of

  motion is;

∵ ∑ forces in direction of motion = mass × acceleration

∵ No external force

∵ The friction force (F) = μR, where μ is coefficient of the frictional force

   and R is the normal reaction of the weight of the particle on the

   surface

∵ The frictional force is in opposite direction of the motion

∴ ∑ forces in the direction of motion = 0 - F

∴ 0 - F = mass × acceleration

- Substitute F by μR

∴ - μR = mass × acceleration

∵ R = mg where m is the mass of the particle and g is the acceleration

  of gravity

∴ - μ(mg) = ma ⇒ a is the acceleration of motion

- By divide both sides by m

∴ - μ(g) = a

∵ The acceleration of gravity ≅ 32 feet/sec²

∴ a = - 32 μ

* Any particle moving in a horizontal plane slowed by friction,

 deceleration = 32 μ

# 2) A particle moving under the action of an external force P in a

  horizontal plane.

- When an external force P acts on the particle, then its equation

 of motion is;

∵ ∑ forces in direction of motion = mass × acceleration

∵ The external force = P

∵ The friction force (F) = μR, where μ is coefficient of the frictional force

   and R is the normal reaction of the weight of the particle on the

   surface

∵ The frictional force is in opposite direction of the motion

∴ ∑ forces in the direction of motion = P - F

∴ P - F = mass × acceleration

- Substitute F by μR

∴ P - μR = mass × acceleration

∵ R = mg where m is the mass of the particle and g is the acceleration

  of gravity

∴ P - μ(mg) = ma ⇒ a is the acceleration of motion

∵ The acceleration of gravity ≅ 32 feet/sec²

∴ P - 32μm = ma ⇒ (1)

- divide both side by m

∴ a = (P - 32μm)/m ⇒ divide the 2 terms in the bracket by m

∴ a = P/m - 32μ

* The particle moving by acceleration = P/m - 32μ

- If you want to fin the external force P use equation (1)

∵ P - 32μm = ma ⇒ add 32μm to both sides

∴ P = ma + 32μm

* The external force = ma + 32μm

7 0
3 years ago
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