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emmainna [20.7K]
3 years ago
15

Cassie has 1/2 pound of sugar in her tablet her cake recipe calls for 2/10 of a pound of sugar how many cakes can she make

Mathematics
1 answer:
AlexFokin [52]3 years ago
7 0

Answer:

2.5 cakes

Step-by-step explanation:

Divide 1/2 into 2/10

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Marcus invested $2000 in a bank account earning simple interest. The interest, I, he has after t years at an interest rate r is
laila [671]

Answer:

4%

Step-by-step explanation:

5 0
3 years ago
I need help on this question
aleksklad [387]

Answer:

Figure G.

Step-by-step explanation:

Let's check through the values and calculate the radius and area for all the circle.

For circle R

Diameter = 2 feet

Radius= 1 feet

Area= πr²

Area= 3.14*1

Area= 3.14 feet²

CircleS

Diameter= 4 feet

Radius= 2 feet

Area= πr²

Area= 3.14*2²

Area= 12.56 feet²

Circle T

Diameter= 8 feet

Radius= 4 feet

Area = π r²

area= 3.14*4²

Area=50.24 feet²

Circle U

Diameter= 12 feet

Radius= 6 feet

Area = π r²

area= 3.14*6²

Area=113.04 feet²

The values of the radius and Area all match the graph in figure G

8 0
3 years ago
I NEED HELP ASAP PLEASE!!!
Artemon [7]

Answer:

-3x+1y=-1

or

3x-1y=1

or

by multiplying with 1/3 the first equation we get

-1x+1/3y=-1/3

or from second equation

1x-1/3y=1/3

Step-by-step explanation:

y-y1=m(x-x1)

y1=-7

x1=-2

m=3

so

y-(-7)=3(x-(-2))

y+7=3(x+2)

y+7=3x+6

-3x+y=6-7

-3x+ 1y= -1

8 0
2 years ago
Please help and explain the question is in the picture
Digiron [165]

Answer: 123 square feet

Step-by-step explanation: The question is a little odd, but I can break it down easily. It wants us to find the area of a three foot border around his room.

First, the whole area of his room is 20 x 24 = 480

Next, we have to make the measurements 3 feet smaller on each wall, so 17 x 21 = 357

Finally, to find the area of the border, we simply do 480 - 357 = 123

He needs to buy 123 square feet of carpeting

Hope this helps!

8 0
3 years ago
Read 2 more answers
This is a question on my partial fractions homework, but no matter what I try I can't figure it out..
Ierofanga [76]
\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{a_1x+a_0}{(x+1)^2}+\dfrac b{x+2}
\implies\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{(a_1x+a_0)(x+2)+b(x+1)^2}{(x+1)^2(x+2)}
\implies x^2+x+1=(a_1+b)x^2+(2a_1+a_0+2b)x+(2a_0+b)
\implies\begin{cases}a_1+b=1\\2a_1+a_0+2b=1\\2a_0+b=1\end{cases}\implies a_1=-2,a_0=-1,b=3

So you have

\displaystyle\int_0^2\frac{x^2+x+1}{(x+1)^2(x+2)}\,\mathrm dx=-2\int_0^2\frac x{(x+1)^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}
=\displaystyle-2\int_1^3\dfrac{x-1}{x^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}

where in the first integral we substitute x\mapsto x+1.

=\displaystyle-2\int_1^3\left(\frac1x-\frac1{x^2}\right)\,\mathrm dx-\frac1{1+x}\bigg|_{x=0}^{x=2}+3\ln|x+2|\bigg|_{x=0}^{x=2}
=-2\left(\ln|x|+\dfrac1x\right)\bigg|_{x=1}^{x=3}-\dfrac23+3(\ln4-\ln2)
=-2\left(\ln3+\dfrac13-1\right)-\dfrac23+3\ln2
=\dfrac23+\ln\dfrac89
4 0
3 years ago
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