Answer:
118 i think
Step-by-step explanation:
-2{-7-2[3 squared + 2 to the power of 4]-8÷4}
-2{-7-2{9+16]-2}
-2{-7-50-2}
-2(-59)
118
Yintercepts are where x=0
set to zero to solve
0^2+4y^2=16
4y^2=16
divide 4
y^2=4
sqrt both sides
y=+/-2
xintercept is where y=0
x^2+4(0)^2=16
x^2+0=16
x^2=16
sdqrtboth sides
x=+/-4
yintercepts are (0,2) and (0,-2)
xintercepts are (4,0) and (-4,0)
Answer:
Step-by-step explanation:
The tough part of this question is figuring out what to do with √(7^2). You could do it by expanding the square. √(7^2) = √49
Now what is the square root of 49? Is it not 7?
√49 = 7
7^6 * 7^1
7 ^(6 + 1)
7 ^ 7
Using PEDMAS, you would divide I/2 first, then add 2 to that and subtract I from the equation. It all varies on what "i" is, however.
