<span>the action or condition of becoming or being made wider, larger, or more open</span>
We can use the points (4, 5) and (8, 10) to solve.
Slope formula: y2-y1/x2-x1
= 10-5/8-4
= 5/4
= 1.25
The answer is [ D. The slope of the graph is 1.25 ]
Best of Luck!
Answer:
Step-by-step explanation:
m=2ov(2.718282)r(7)
Answer:
m=38.055946orv
I think hope this is correct
Answer:
0.7611 = 76.11% probability that the weight of a randomly selected steer is less than 1140lbs.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 900, \sigma = 300](https://tex.z-dn.net/?f=%5Cmu%20%3D%20900%2C%20%5Csigma%20%3D%20300)
Find the probability that the weight of a randomly selected steer is less than 1140lbs.
This is the pvalue of Z when X = 1140. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{1140 - 900}{300}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B1140%20-%20900%7D%7B300%7D)
![Z = 0.71](https://tex.z-dn.net/?f=Z%20%3D%200.71)
has a pvalue of 0.7611
0.7611 = 76.11% probability that the weight of a randomly selected steer is less than 1140lbs.