Answer:
sorry abs
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
A'(-2*3/2=-3,3*3/2=4.5), B'(-6,-6), C'(6,0), D'(7.5,6)
The formula
in solving the integral of the infinity of 3 is ∫3<span>∞?</span>(1<span>)÷((</span>x−2<span><span>)<span><span>(3/</span><span>2)</span></span></span>)</span><span>dx</span>
Substitute the numbers given
then solve
limn→inf∫3n(1/((n−2)(3/2))dn
limn→inf[−2/(n−2−−−−−√)−(−2/3−2−−−−√)
=0+2=2
Solve for the integral of 2 when 2 is approximate to 0.
Transpose 2 from the other side to make it -2
∫∞3(x−2)−3/2dx=(x−2)−1/2−1/2+C
(x−2)−1/2=1x−2−−−−√
0−(3−2)−1/2−1/2=2
<span> </span>
Given:
To find:
The values of f(2) and f(5).
Solution:
If an ordered pair 
is in the function 
, then 
.
In the given set of ordered pairs one ordered pair is (2,3). So, by using the above definition, we get
In the given set of ordered pairs one ordered pair is (5,6). So, by using the above definition, we get
Therefore, the value of f(2) is 3 and the value of f(5) is 6.
