Explanation:
The given data is as follows.
Mass of refrigerant, m = 10 kg
Volume of the refrigerant, V = 1.595 
Formula for specific volume of the refrigerant is as follows.
v = 
= 0.1595 
So, at
specific volume will be within
and
and pressure is constant.
The fluid will be in super-heated state at temperature
and at T =
pressure 1 bar = 0.1 MPa.
According to super-heated tables, the specific volume is v = 0.30138
.
Hence, the final volume will be calculated as follows.

= 
= 3.0138 
Thus, we can conclude that final volume of the R-134a is 3.0138
.
2h-7 I had that before unless I’m tripping but I did rechecked
Answer:
Explanation:
Using the ideal gas equation as follows:
PV = nRT
Where:
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
Based on the information provided in this question;
P = 1.6atm
n = 4.4 moles
R = 0.0821 L*atm/mol*K
T = 32.9°C = 32.9 + 273 = 305.9K
V = ?