Answer:
CaCO3(s) <==> Ca2+(aq) + CO3 2-(aq)
Let X = the amount of CaCO3 dissolved in Na2CO3 or the amount of each ions formed i.e. Ca2+ and CO3 2–. Then, put this into the formula :
Ksp = [Ca2+] [CO3 2-]
5 × 10^-9 = [X]*[X]
X^2 = 5 × 10^-9
X = √5 × 10^-9
X = 7.07 x 10^-5 mole/L
So, the amount of CaCO3 dissolved in 0.1M Na2CO3 or the amount of Ca2+ and CO3 2- ions produced is 7.07 x 10^-5 mole/L
<h3>
Answer:</h3>
16.7 g H₂O
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Stoichiometry</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] 2NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)
[Given] 1.85 mol NaOH
<u>Step 2: Identify Conversions</u>
[RxN] 2 mol NaOH → 1 mol H₂O
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Stoichiometry</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
16.6685 g H₂O ≈ 16.7 g H₂O
Hello my friend, Ionic bond is created when one atom takes an electron from another to fill its valence shell. Hope it helps☺☺
If you look at the periodic table, Krypton has an atomic number of 36. Krypton is one of the noble gases. They are a group of elements that are very stable because they obey the Octet Rule. As a result, other elements try to conform the electronic configurations of the nearest noble gases to them. They either give or take electrons in their valence shell.
The three atoms that have 36 electrons are: Kr (Krypton), Br⁻ (Bromide), and Rb⁺(Rubidium ion).