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3 years ago

Help please I need it

Chemistry

1 answer:

anastassius [24]3 years ago

8 0

2 and 4 i think sorry if wrong

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Nuetrons+protons. and number 7 is electrons and protons

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During which changes of state do atoms that cannot move past one another become free to move?

Ipatiy [6.2K]

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3 miles of NaCl in 12 liters of water <br> What is the molarity

lesya [120]

Answer:

$12 \: litres \: contain \: 3 \: \: moles \: of \: sodium \: chloride \\ 1 \: litre \: will \: contain \: \frac{(1 \times 3)}{12} moles \\ = 0.25 \: mol \: {l}^{ - 1}$

Explanation:

$12 \: litres \: contain \: 3 \: \: moles \: of \: sodium \: chloride \\ 1 \: litre \: will \: contain \: \frac{(1 \times 3)}{12} moles \\ = 0.25 \: mol \: {l}^{ - 1} \\ or : 0.25 \: M$

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Can someone please explain core and valence electrons in periods for me please

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Answer:

The electrons of an atom are typically divided into two categories: valence and core electrons. Valence electrons occupy the outermost shell or highest energy level of an atom while core electrons are those occupying the innermost shell or lowest energy levels

Explanation:

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3 years ago

In the reaction between bromine and sodium, a bromine atom gains an electron. What ion is formed? Is the bromine oxidized, or is

SVETLANKA909090 [29]

Answer: The ion formed after the reduction of bromine is $Br^-$

Explanation:

The electronic configuration of Sodium (Na) = $[Ne]3s^1$

The electronic configuration of Bromine (Br) = $[Ar]3d^{10}4s^24p^5$

From the above configurations, Sodium ion will loose 1 electron in order to gain stable electronic configuration and that electron is accepted by the Bromine atom because it is 1 electron short of the stable electronic configuration.

$Na\rightarrow Na^++e^-$ (oxidation reaction)

$Br+e^-\rightarrow Br^-$ (Reduction reaction)

Bromine atom is reduced to form $Br^-$

Reduction reactions are the reactions in which the element gain electrons.

Oxidation reactions are the reactions in which the element looses its electrons.

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4 years ago

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