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WARRIOR [948]
3 years ago
7

Consider the following reversible reaction.

Chemistry
2 answers:
Lelechka [254]3 years ago
8 0

Answer:

K = [CO2] / [O2]

Explanation:

The formula is K = [product] / [reactant].

C is excluded because it is a solid. And the rule says when there's a solid with other gases, only the gases will be considered for the equilibrium constant expression

zvonat [6]3 years ago
6 0

<u>Answer:</u> The expression of equilibrium constant for the given equation is K_{eq}=\frac{[CO_2]}{[O_2]}

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

C(s)+O_2(g)\rightleftharpoons CO_2(g0

The expression of K_{eq} for above equation follows:

K_{eq}=\frac{[CO_2]}{[O_2]}

Hence, the expression of equilibrium constant is written above.

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