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ANEK [815]
3 years ago
9

Story that ends in i have never found such a kind person ever since ​

Chemistry
1 answer:
zmey [24]3 years ago
7 0

Answer:

I was traveling on a train where I fell asleep. someone stole my luggage in which I had money and other essentials. when the ticket checker arrived a lady paid my fine. she helped me a lot. when I told her about being robbed she helped me and took me to the police station and I found my bag. I insisted she take the money she paid for my fine but she said that in return you too help someone."I have never found such a kind person ever since.".....

Explanation: I think this is what you are looking for. Hope this helps.

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Suppose that 0.250 mol of methane, CH4(g), is reacted with 0.400 mol of fluorine, F2(g), forming CF4(g) and HF(g) as sole produc
shtirl [24]

300 gallons

Explanation:

7 0
3 years ago
A rectangular block of solid carbon (graphite) floats at the interface of two immiscible liquids.
Sergio039 [100]

Explanation:

Let us take the volume of block is x.

Since, the block is floating this means that it is in equilibrium. Formula to calculate net force will be as follows.

                F_{net} = Buoyancy force(F_{b}) - weight force(w)

Also, buoyancy force (F_{b}) = (volume submerged in water × density of water) + (volume in oil × density of oil)

          (F_{b}) = (0.592 V \times \rho) + (1 - 0.592)V \times 1000 g          

                      = (0.592 V \times \rho + 408 V) g

As,   W = V × density of graphite × g

It is given that density of graphite is 2.16 g/cm^{3} or 2160 kg/m^{3}.

So, W = 2160 V g

F_{net} = (0.592 V \rho + 408 V) g - 2160 V g = 0

            0.592 \rho = 1752

     \rho = 2959.46 kg/m^{3} or 2.959 g/cm^{3} is the density of oil.

It is given that mass of flask is 124.8 g.

Mass of 35.3 cm^{3} oil = 35.3 \times 2.959 104.7 g

Hence, in second weighing total mass will be calculated as follows.

                       (124.8 + 104.7) g

                       = 229.27 g

Thus, we can conclude that in the second weighing mass is 229.27 g.

5 0
3 years ago
El agua del mar contiene aproximadamente un 3,0 % m/v de sal (NaCl, 58,44 g/mol), (asuma que es la única fuente de cloruros) si
Alchen [17]

Answer:

s = 4.41 g/L.

Explanation:

¡Hola!

En este caso, considerando el escenario dado, se hace necesario para nosotros saber que la posible reacción de disociación la experimenta el cloruro de plomo (II) como se muestra a continuación:

PbCl_2(s)\rightleftharpoons 2Cl^-(aq)+Pb^{2+}(aq)

Lo cual hace que la expresión de equilibrio se calcule como:

Ksp=[Pb^{2+}][Cl^-]^2

Y que en términos de la solubilidad molar, s, se resuelve como:

1.6x10^{-5}=s(2s)^2\\\\1.6x10^{-5}=4s^3\\\\s=\sqrt[3]{\frac{1.6x10^{-5}}{4} } \\\\s=0.0159molPbCl_2/L

Ahora, convertimos este valor a g/L al multiplicarlo por la masa molar del cloruro de plomo (II):

s=0.0159molPbCl_2/L*\frac{278.1gmolPbCl_2}{1molmolPbCl_2} \\\\s=4.41g/L

¡Saludos!

7 0
3 years ago
What is the correct name for: C3S5?
scZoUnD [109]

Answer:

Trithioxodithiole

Explanation:

5 0
3 years ago
What is the answer to 1 and 2?
ankoles [38]
You got the questions correct
4 0
3 years ago
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