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Zina [86]
2 years ago
12

The molar mass of barium nitrate (ba(no3)2) is 261.35 g/mol. what is the mass of 5.30 × 1022 formula units of ba(no3)2? 0.0900 g

12.0 g 23.0 g 3,130 g
Chemistry
1 answer:
liberstina [14]2 years ago
6 0

Molar mass is the ratio of the mass to that amount of the substance. The mass of the barium nitrate in the formula unit is 23.0 grams.

<h3>What is mass?</h3>

The mass of a substance is the product of the molar mass of the compound and the number of moles of the compound.

Given,

Molar mass of barium nitrate = 261.35 g/mol

If, 6.022 \times 10^{23} have a mass of 261.35 g/mol then, 5.30 \times 10^{22} formula units will have a mass of,

\begin{aligned}& = \dfrac{261.35 \times 5.30 \times 10^{22}}{6.022\times 10^{23}}\\\\&= 23.0\;\rm gm\end{aligned}

Therefore, option C. 23.0 gm is the mass of barium nitrate.

Learn more about mass here:

brainly.com/question/24958554

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6 0
3 years ago
What volume of 1.00 m hcl in liters is needed to react completely (with nothing left over) with 0.750 l of 0.100 m na2co3?
kotykmax [81]
The balanced equation for the reaction is as follows
Na₂CO₃ + 2HCl --> 2NaCl + CO₂ + H₂O
stoichiometry of Na₂CO₃ to HCl is 1:2
number of Na₂CO₃ moles reacted = molarity x volume
number of Na₂CO₃ moles = 0.100 mol/L x 0.750 L = 0.0750 mol 
according to molar ratio of 1:2
1 mol of Na₂CO₃ reacts with 2 mol of HCl
then 0.0750 mol of Na₂CO₃ mol reacts with - 2 x 0.0750 = 0.150 mol 
molarity of given HCl solution is 1.00 mol/L
molarity is defined as the number of moles of solute in 1 L of solution 
there are 1.00 mol in 1 L of solution 
therefore there are 0.150 mol in - 0.150 mol / 1.00 mol/L = 0.150 L 
volume of HCl required is 0.150 L 
3 0
3 years ago
Why does our body need to use both mechanical and chemical digestion when we are breaking down our food?
melomori [17]

Answer:

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Explanation:

5 0
3 years ago
Balance the following reaction and use the equation to calculate the ΔHrxn. C3H8(g) + O2(g) → CO2(g) + H2O(g) Round your answer
gladu [14]

The reaction corresponds to the combustion of propane (C3H8). The balanced reaction is:

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

The reaction enthalpy is given as:

ΔHrxn = ∑nΔH°f(products) - ∑ nΔH°f(reactants)

          = [3ΔH°f(CO2(g)) + 4ΔH°f(H2O(g)] - [1ΔH°f(C3H8(g)) + 5ΔH°f(O2(g)]

          = [3(-393.5) + 4(-241.8)] - [-103.9 + 5(0)] = -2043.8 kJ

The enthalpy for the combustion of propane is -2044 kJ

4 0
3 years ago
Considering that the mantle is 44.8% oxygen and 21.5% silicon by mass, calculate the mole ratio of oxygen atoms to silicon atoms
horrorfan [7]

The mantle has a mass of around 4.278 X 10 ^2^4 kg that is around 68.4% of earth's mass.

So to calculate moles we need to first find out the mass of oxygen and silicon present in mantle. It is given that oxygen is 44.8% by mass in mantle and 21.5% by mass in mantle, therefore to calculate its mass, we need to use \text{mass percentage }=\frac{\text{mole of solute}}{\text{mass of solution}}\times100

Now, to calculate mass percentage of oxygen

44.8 =\frac{x}{4.278X10^2^4kg}\times100

x= 191.65\times10^2^2kg

Similarly the mass of silicon can be calculated

21.5 =\frac{x}{4.278X10^2^4kg}\times100

x=91.977\times10^2^2kg

Now, the moles of any substance is calculated by

\text{moles}= \frac{\text{given mass}}{\text{molar mass}}

\text{moles of oxygen}= \frac{191.65\times10^2^2kg}{2.6566962\times10^-^2^6kg}

where, mass of oxygen in kilograms is 2.6566962\times10^-^2^6kg

So,\text{moles of oxygen}=72.1384\times10^4^8\text{moles of O}

Similarly \text{moles of silicon}= \frac{91.977\times10^2^2kg}{4.663\times10^-^2^6kg}

\text{moles of silicon}=19.724\times10^4^8\text{moles of Si}

Now, to calculate mole ratio we need to divide every moles to the lowest calculated mole that is the moles of Si and round it off to the nearest whole number.

\text{mole ratio of oxygen}= \frac{72.138\times10^4^8kg}{19.724\times10^4^8kg}

=3.65\approx 4

\text{mole ratio of Silicon}=\frac{19.724\times10^4^8}{19.724\times10^4^8}

=1

\text{Mole ratio of Oxygen : Mole ratio of Silicon} = 4:1


6 0
4 years ago
Read 2 more answers
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