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brilliants [131]
3 years ago
9

If two lines are perpendicular, then they form:

Mathematics
2 answers:
Alexandra [31]3 years ago
7 0
A cross because they are intersecting each other at the center of each line.
zhuklara [117]3 years ago
5 0
If two lines are perpendicular, they form a 90° angle, or a right angle. By definition, two perpendicular lines intersect at a right angle. For instance, a vertical line and a horizontal line will cross at a 90° angle.

I
I
I_
I_I______

Here is a (very crude) sketch of two perpendicular lines. The box between the place where the lines intersect indicates a right angle.

Hope this helps!
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fifteen (15) birthday cues.

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3 years ago
if a scatter plot has no association then... A.) it has no ordered psirs B.) its ordered pairs have no predictable pattern C.) i
musickatia [10]

Answer:

If a scatter plot has no association then it's ordered pairs have no predictable pattern.  

Step-by-step explanation:

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3 years ago
WORTH 50! WILL AWARD BRAINLIEST! 5 QUESTIONS! SHOW STEPS PLEASE!
Vesnalui [34]
I dont get it LOL but im doing this too so maybe you can help me too?
5 0
2 years ago
Simplify -2(4f+6)+3(4f-6)
hoa [83]
It will be 4f-30. Using substitution, you get (-8f-12) + (12f-18). Adding this together you get -8f-12+12f-18. Then you add -8f and 12f to get 4f, and add -12 and -18 to get -30. 
4 0
3 years ago
Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2
Anastaziya [24]

Answer:

\displaystyle  \frac{dy}{dx} =    \frac{2x + 2}{x^3}

Step-by-step explanation:

we would like to figure out the derivative of the following:

\displaystyle  \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }

to do so, let,

\displaystyle y =  \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }

By simplifying we acquire:

\displaystyle y =  3 -  \frac{2}{x}  -  \frac{1}{ {x}^{2} }

use law of exponent which yields:

\displaystyle y =  3 -  2 {x}^{ - 1}  -   { {x}^{  - 2} }

take derivative in both sides:

\displaystyle  \frac{dy}{dx} =  \frac{d}{dx}  (3 -  2 {x}^{ - 1}  -   { {x}^{  - 2} } )

use sum derivation rule which yields:

\rm\displaystyle  \frac{dy}{dx} =  \frac{d}{dx}  3 -   \frac{d}{dx} 2 {x}^{ - 1}  -     \frac{d}{dx} {x}^{  - 2}

By constant derivation we acquire:

\rm\displaystyle  \frac{dy}{dx} =  0 -   \frac{d}{dx} 2 {x}^{ - 1}  -     \frac{d}{dx} {x}^{  - 2}

use exponent rule of derivation which yields:

\rm\displaystyle  \frac{dy}{dx} =  0 -   ( - 2 {x}^{ - 1 -1} ) -     ( - 2 {x}^{  - 2 - 1} )

simplify exponent:

\rm\displaystyle  \frac{dy}{dx} =  0 -   ( - 2 {x}^{ -2} ) -     ( - 2 {x}^{  - 3} )

two negatives make positive so,

\displaystyle  \frac{dy}{dx} =   2 {x}^{ -2} +      2 {x}^{  - 3}

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

\displaystyle  \frac{dy}{dx} =   \frac{2 }{x^2}+       \frac{2}{x^3}

simplify addition:

\displaystyle  \frac{dy}{dx} =    \frac{2x + 2}{x^3}

and we are done!

5 0
3 years ago
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