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3 years ago

11

What is the orbital diagram of Ni^2+?

1 answer:

Crazy boy [7]3 years ago

4 0

Answer is 3d 4s

and I suggest to also download Socratic it is also very helpful

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Who wants to play truth or dare

natima [27]

Iam willing to play truth and dare

Explanation:

because I love to play truth and dare

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2 years ago

Read 2 more answers

For the equilibrium

Mamont248 [21]

Answer:

Equilibrium concentrations of the gases are

$H_2S=0.596M$

$H_2=0.004 M$

$S_2=0.002 M$

Explanation:

We are given that for the equilibrium

$2H_2S\rightleftharpoons 2H_2(g)+S_2(g)$

$k_c=9.0\times 10^{-8}$

Temperature, $T=700^{\circ}C$

Initial concentration of

$H_2S=0.30M$

$H_2=0.30 M$

$S_2=0.150 M$

We have to find the equilibrium concentration of gases.

After certain time

2x number of moles of reactant reduced and form product

Concentration of

$H_2S=0.30+2x$

$H_2=0.30-2x$

$S_2=0.150-x$

At equilibrium

Equilibrium constant

$K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}$

Substitute the values

$9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}$

$9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}$

$9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}$

By solving we get

$x\approx 0.148$

Now, equilibrium concentration of gases

$H_2S=0.30+2(0.148)=0.596M$

$H_2=0.30-2(0.148)=0.004 M$

$S_2=0.150-0.148=0.002 M$

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3 years ago

Draw a schematic diagram of a circuit with an output device, a energy source and a controller.

mart [117]

Answer:

ch∪pαpi munαn0?

Explanation:

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I AM GETTING TIMED! PLEASE HELP ME!!

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Explanation:

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3 years ago

Which is NOT a component of the kinetic theory of matter?

Vika [28.1K]

Answer:

1) all matter is made up of atoms and molecules 2) these tiny particles are always in motion; the higher the temp. the faster they move 3) at the same temp., heavier particles move more slowly then small particles

Explanation:

5 0

3 years ago