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goblinko [34]
3 years ago
15

Find the area of the shaded region.

Mathematics
1 answer:
slamgirl [31]3 years ago
7 0

Answer:

25,886 in²

Step-by-step explanation:

The given figure shows 2 circles centered at the same point. We need to find the area of the shaded region. If we observe carefully, the area in between two circles is the shaded region. So if we subtract the Area of smaller circle from the Area of larger circle we can calculate the Area of the shaded region.

Area of a circle = πr²

Radius of larger circle = OP = OQ = 93.4 inches

Radius of smaller circle = OR = OQ - RQ = 93.4 - 71.5 = 21.9 inches

Therefore, area of shaded region will be:

Area of Shaded Region = Area of larger circle - Area of smaller circle

Area of Shaded Region = π(93.4)² - π(21.9)²= 25,886 in²

Thus, the area of shaded region, rounded to nearest inch will be 25,886 in²

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When The Product of 15 and 40 is divided by the sum of 15 and 45 what is the quotient?
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Answer:

10

Step-by-step explanation:

(15 x 40) / (15+40)

solve inside the parenthesis:

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2 years ago
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
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Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

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Step-by-step explanation:

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