Let's say 
. Let's find point 
so that we can find 
.
- Leah walks 40 yards south.
- Leah walks 60 yards west.
- Leah walks 10 yards north.
- Leah walks 20 yards east.
We have found that 
.
Now think about this scenario visually. We started at the center of something, which we call point 
, and then started moving around until we got to point . We can then form line between the points. However, realize that we can actually make a triangle. Just think of one of the legs as part of the x-axis and the other leg as part of the y-axis.
We can find the length of these parts, which is simply the absolute value of the coordinates of point . It may be a little hard to think about, but essentially, we can form a triangle with sides that consist of part of the x-axis, part of the y-axis, and . We also know that the lengths of the legs are 40 and 30.
Since we are given the two lengths of the legs on the triangle and trying to find the length of the hypotenuse, we can use the Pythagorean Theorem. This states:
and 
are the lengths two legs of the triangle
is the length of the hypotenuse
Thus, substituting in our values, we find:
The length of is 50.
Answer: 44 years
Step-by-step explanation:
Let Brita's age be x and the daughter's age be y , then from the first statement :
From the second statement :
solving the resulting linear equation , add the two equations , we have
substitute 74 into equation 1 to find the value of y
Therefore :
Eva = 44 years
Given :
Initial length of electric cable needed, 
.
Later, Sally is told that the homeowner has decide to cut back from a three-car garage to a two-car garage, which will eliminate two branch circuits, one of 23 feet and the other of 34 feet.
To Find :
How many feet of wire will be needed now.
Solution :
Wire needed is given by :
Required = Total wire - ( length of 1nd branch + length of 2nd branch )
Required = 550 - ( 23 + 34 )
Required = 550 - ( 57 ) ft
Required = 443 ft
Therefore, length of wire required is 443 ft.
Hence, this is the required solution.
Ill say, C) Place the compass' point on the other end of the segment.
