All categories

2 years ago

chord ab intersects chord hi at point c.the length of cb is 4 times the length of ac.find the length of ac

1 answer:

5 0

Chord AB = ?
Chord AB = AC + CB

Chord HI = HC + CI
HC = 7
CI = 28
Chord HI = 7 + 28 = 35

Chord AB = Chord HI

CB is 4 times the Length of AC. Let AC be X.

x + 4x = 35
5x = 35
x = 35/5
x = 7

AC = x = 7
CB = 4x = 4(7) = 28

You might be interested in

8 sided die probability of rolling odd number

Elena L [17]

Answer: 4 I think . not sure

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Which of the following is the y-intercept of the line with the equation 2y=6x+4

algol [13]

It is y = 3x + 2, which means the y-intercept is 2. :)

8 0

3 years ago

I NEED HELP PLEASE! :)<br> thanks

luda_lava [24]

Formula: A = pq/2

p = d1

q = d2

Substitute with the given values and solve.

A = 12*14/2

A = 168/2

A = 84

Therefore, the ansewr is 84in²

Best of Luck!

3 0

3 years ago

A particle, initially at rest, moves along the x-axis such that its acceleration at time t > 0 is given by a(t) = 6cos(t). At

Rom4ik [11]

a. By the fundamental theorem of calculus, the velocity function is

$v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du$

The particle starts at rest, so $v(0)=0$ , and we have

$v(t)=\displaystyle\int_0^t6\cos u\,\mathrm du=6\sin u\bigg|_0^t=6\sin t$

Then the position function is

$x(t)=\displaystyle x(0)+\int_0^tv(u)\,\mathrm du$

with $x(0)=6$ , so

$x(t)=6+\displaystyle\int_0^t6\sin u\,\mathrm du=6-6\cos u\bigg|_0^t=12-6\cos t$

b. The particle is at rest whenever $v(t)=0$ ; this happens for

$6\sin t=0\implies \sin t=0\implies t=n\pi$

where $n$ is any integer.

3 0

2 years ago

Monica uses 1/3 of a pint of hair gel a day. How much does she use in 4 days

sdas [7]

She uses 4/3 (1 1/3) pint of hair gel in 4 days

5 0

2 years ago

Read 2 more answers