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3 years ago

Solve the literal equation for c 4p+9c=p

Mathematics

2 answers:

zimovet [89]3 years ago

5 0

4p+9c=p

move 4p to the other side

sign changes from +4p to -4p

4p-4p+9c=p-4p

9c= p-4p

9c= -3p

divide both sides by 9 to get c by itself

9c/9= -3p/9

c= -3p/9

reduce by dividing by 3

-3p/3= -p

9/3= 3

Answer:

c= -p/3

s344n2d4d5 [400]3 years ago

4 0

Answer:

c = -p/3.

Step-by-step explanation:

4p+9c=p

9c = p - 4p

9c = -3p

c = -3p/9

c = -p/3.

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A sample of 20 joint specimens of a particular type gave a sample mean proportional limit stress of 8.41 mpa and a sample standa

nignag [31]

For this problem, the confidence interval is the one we are looking for. Since the confidence level is not given, we assume that it is 95%.

The formula for the confidence interval is: mean ± t (α/2)(n-1) * s √1 + 1/n

Where:

α= 5%

α/2 = 2.5%

t 0.025, 19 = 2.093 (check t table)

n = 20

df = n – 1 = 20 – 1 = 19

So plugging in our values:

8.41 ± 2.093 * 0.77 √ 1 + 1/20

= 8.41 ± 2.093 * 0.77 (1.0247)

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3 years ago

Please help me 33/2 + 3y/5 = 7y/10 + 15

8090 [49]

We are given with an equation in variable y and we need to solve for y . So , now let's start !!!

We are given with ;

${:\implies \quad \sf \dfrac{33}{2}+\dfrac{3y}{5}=\dfrac{7y}{10}+15}$

Take LCM on both sides :

${:\implies \quad \sf \dfrac{165+6y}{10}=\dfrac{7y+150}{10}}$

Multiplying both sides by 10 ;

${:\implies \quad \sf \cancel{10}\times \dfrac{165+6y}{\cancel{10}}=\cancel{10}\times \dfrac{7y+150}{\cancel{10}}}$

${:\implies \quad \sf 165+6y=7y+150}$

Can be further written as ;

${:\implies \quad \sf 7y+150=165+6y}$

Transposing 6y to LHS and 150 to RHS

${:\implies \quad \sf 7y-6y=165-150}$

${:\implies \quad \bf \therefore \quad \underline{\underline{y=15}}}$

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