Write the Lewis structure for the product that forms when boron trifluoride combines with ammonia. Remember to show all non-zero
formal charges and all lone pairs of electrons.
1 answer:
Answer:
To draw or sketch a Lewis structure, formula or diagram, the chemical formula of the compound is essential. Without it you can not even know what are the atoms that make it up, in our case it is the one observed in the reaction shown:
+
⇒ F3
In the structure obtained (see the Lewis structure in the drawing) the black dots correspond to the electrons of the non-shared pairs. Because hydrogen has a single electron and a single orbital available to fill, it forms only a covalent bond represented by a long dash. The same goes for boron and fluorine but in this case the fluorine has pairs of free electrons.
Explanation:
Lewis's structure is all that representation of covalent bonds within a molecule or an ion. In it, said bonds and electrons are represented by long dots or dashes, although most of the times the dots correspond to non-shared electrons and dashes to covalent bonds.
All existing compounds can be represented by Lewis structures, giving a first approximation of how the molecule or ions could be.
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Answer:- 123 amu.
Solution:- The formula to calculate the average atomic mass of an atom is:
Average atomic mass = mass of first isotope(abundance of first isotope) + mass of second isotope(abundance of second isotope)
Note: The percent abundance is converted to decimals.
mass of Sb-121 is 121 amu and it's percent abundance is 57.3% and in decimal it is 0.573. Percent abundance of Sb-123 is 42.8% and in decimal it is 0.428. We are asked to calculate it's mass. The average atomic mass of Sb is given as 122.
Let's say the mass of Sb-123 is M and plug in the values in the formula and do calculations:
122 = 121(0.573) + M(0.428)
122 = 69.333 + M(0.428)
On rearrangement:-
M(0.428) = 122 - 69.333
M(0.428) = 52.667
M = 123
So, the mass of Sb-123 is 123 amu.