ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana ImAbananaImAbananaImAbanana ImAbanana
Answer: Our required probability is 0.004672.
Step-by-step explanation:
Since we have given that
Number of adults = 7
Probability of getting adult will watch prime time TV live = 0.8
We need to find the probability that fewer than 3 of the selected adults watch prime time live.
We will use "Binomial Distribution":
here, n = 7
p = 0.8
So, P(X<3)=P(X=0)+P(X=1)+P(X=2)
So, it becomes,


So, probability that fewer than 3 of the selected adult watch prime time live is given by

Hence, our required probability is 0.004672.
Answer:
x=29
Step-by-step explanation:
−3(3+x)+4(x−6)=−4
(−3)(3)+(−3)(x)+(4)(x)+(4)(−6)=−4(Distribute)
−9+−3x+4x+−24=−4
(−3x+4x)+(−9+−24)=−4(Combine Like Terms)
x+−33=−4
x−33=−4
Step 2: Add 33 to both sides.
x−33+33=−4+33
x=29
I hope this helps