Answer:
a. Sage and Tom have the same number of talk minutes left on their cell phone plans.
b. y = x - 7
Explanation:
Sage talked for 7 minutes with her dad.
Tom talked for 4 minutes with a friend and 3 more minutes with his mom which means he spoke for :
= 4 + 3
= 7 minutes
They both spoke for 7 minutes and therefore have the same amount of time left.
Algebraic expression:
Assuming the time Tom started with is denoted by x and the time he is left with is denoted by y.
The expression is:
y = x - 7
His average is 86 so it is below 90. to get his average i just added all of his grades up to get 517 and then I divided 517 by 6 because thats how many grades he has and I got 86.
On the Grade row in the table it would go 83, 94, 79, 90, 96, 75 in order
The Above/Below 90 row would go -7, 4, 11, 7, -6, -3 in order
Lamont needs to get a 99 on his next test to have an average of exactly 90.
I HOPE THIS HELPED! PLEASE RATE ME AND MAKE MY ANSWER MOST BRAINLIEST!!
Answer:
The best buy item is the Frito-Lay mi Variety Pack. Going for only 0.35 per item.
Step-by-step explanation:
All I did was the equations and then I compared the answer, the lowest answer is the best buy since it is the lowest price found.
Frito-Lay:
9.88/28 = 0.35
Unit rate is 35 cents
Pringles:
6.48/18 = 0.36
Unit rate is 36 cents
Pack of 18:
11.21/18 = 0.6
Unit rate is 60 cents
Pack of 24:
15.85/24 = 0.66
Unit rate is 66 cents
GC:
14.75/30 = 0.49
Unit rate is 49 cents
Sweet Treats:
10.75/25 = 0.43
Unit rate is 43 cents
Comparing all of this data, it can easily be seen that the Frito-Lay mi Variety Pack is the best deal you can find out of these 6 deals.
x = total amount split between Adam and Tom.
since we know the total amount split between both in a 18 : 17 ratio is "x", let's divide "x" by (18 + 17) and distribute accordingly to get the amount of each.
![\stackrel{Adam~received}{18\cdot \cfrac{x}{18+17}}\qquad \qquad \stackrel{Tom~received}{17\cdot \cfrac{x}{18+17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since we know that Adam got "5" more}}{ \stackrel{Adam}{18\cdot \cfrac{x}{18+17}}~~ = ~~\stackrel{Tom}{17\cdot \cfrac{x}{18+17}~~ + ~~5} }\qquad \implies \qquad \cfrac{18x}{35}~~ + ~~\cfrac{17x}{35}+5](https://tex.z-dn.net/?f=%5Cstackrel%7BAdam~received%7D%7B18%5Ccdot%20%5Ccfrac%7Bx%7D%7B18%2B17%7D%7D%5Cqquad%20%5Cqquad%20%5Cstackrel%7BTom~received%7D%7B17%5Ccdot%20%5Ccfrac%7Bx%7D%7B18%2B17%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bsince%20we%20know%20that%20Adam%20got%20%225%22%20more%7D%7D%7B%20%5Cstackrel%7BAdam%7D%7B18%5Ccdot%20%5Ccfrac%7Bx%7D%7B18%2B17%7D%7D~~%20%3D%20~~%5Cstackrel%7BTom%7D%7B17%5Ccdot%20%5Ccfrac%7Bx%7D%7B18%2B17%7D~~%20%2B%20~~5%7D%20%7D%5Cqquad%20%5Cimplies%20%5Cqquad%20%5Ccfrac%7B18x%7D%7B35%7D~~%20%2B%20~~%5Ccfrac%7B17x%7D%7B35%7D%2B5)
![\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{35}}{35\left( \cfrac{18x}{35} \right)~~ = ~~35\left( \cfrac{17x}{35}+5 \right)}\implies 18x~~ = ~~17x+175\implies \boxed{x =175} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{Tom~received}{17\cdot \cfrac{x}{18+17}}\implies \cfrac{17(175)}{35}\implies \blacktriangleright 85 \blacktriangleleft](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20%7D%5Cstackrel%7BLCD%7D%7B35%7D%7D%7B35%5Cleft%28%20%5Ccfrac%7B18x%7D%7B35%7D%20%5Cright%29~~%20%3D%20~~35%5Cleft%28%20%5Ccfrac%7B17x%7D%7B35%7D%2B5%20%5Cright%29%7D%5Cimplies%2018x~~%20%3D%20~~17x%2B175%5Cimplies%20%5Cboxed%7Bx%20%3D175%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7BTom~received%7D%7B17%5Ccdot%20%5Ccfrac%7Bx%7D%7B18%2B17%7D%7D%5Cimplies%20%5Ccfrac%7B17%28175%29%7D%7B35%7D%5Cimplies%20%5Cblacktriangleright%2085%20%5Cblacktriangleleft)
Answer:
F(x)=2x^2
Step-by-step explanation:
Basically, a quadratic function has x^2 in it (standard form ax^2+bx+c with non-zero a). The others have x^3, -x, x^4, etc., which clearly are NOT x^2.
