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Travka [436]
3 years ago
14

A "half-reaction” is one which may:

Chemistry
1 answer:
DaniilM [7]3 years ago
8 0

Answer:

d

Explanation:

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Calculate the freezing point of a 0.08500 m aqueous solution of nano3. the molal freezing-point-depression constant of water is
Citrus2011 [14]
Depression in freezing point (ΔT_{f}) = K_{f}×m×i,
where, K_{f} = cryoscopic constant = 1.86^{0} C/m,
m= molality of solution = 0.0085 m
i = van't Hoff factor = 2 (For NaNO_{3})

Thus, (ΔT_{f}) = 1.86 X 0.0085 X 2 = 0.03162^{0}C

Now, (ΔT_{f}) = T^{0} - T
Here, T = freezing point of solution
T^{0} = freezing point of solvent = 0^{0}C
Thus, T = T^{0} - (ΔT_{f}) = -0.03162^{0}C
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3 years ago
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An aqueous solution that has a hydrogen ion concentration of 1.0 x 10^-8 mole per liter has a pH of
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7 0
3 years ago
adam wants to investigate the strengths of different acids and alkalis. He has 2 different acid solutions and 2 different alkali
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Answer:

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(See answer for the explanation)

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c) nervous and endocrine system

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