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3 years ago

Whats is tge electron configuration of Ag2+ please answer asap..

Chemistry

1 answer:

Triss [41]3 years ago

6 0

Answer:

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10

Explanation:

To write the configuration for the Silver and the Silver ion, first we need to write the electron configuration for just Silver (Ag). We first need to find the number of electrons for the Ag atom (there are 47 electrons) using the Periodic Table. When we write the configuration, we'll put all 47

Either way, the Silver electron configuration will be 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s1

Note that when writing the electron configuration for an atom like Ag and Ag+, the 4d is usually written before the 5s. Both of the configurations have the correct numbers of electrons in each orbital, it is just a matter of how the electronic configuration notation is written (see below for an explanation why).

For the Ag+, called the Silver ion, we remove one electron from 5s2 leaving us with:

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10

You might be interested in

How many molecules are in 6.0g of sodium phosphate?

Phantasy [73]

Answer:

2.2 x 10²² molecules.

Explanation:

Firstly, we need to calculate the no. of moles in (6.0 g) sodium phosphate:

no. of moles = mass/molar mass = (6.0 g)/(163.94 g/mol) = 0.0366 mol.

It is known that every mole of a molecule contains Avogadro's number (6.022 x 10²³) of molecules.

using cross multiplication:

1.0 mole of sodium phosphate contains → 6.022 x 10²³ molecules.

0.0366 mole of sodium phosphate contains → ??? molecules.

∴ The no. of molecules in 6.0 g of sodium phosphate = (6.022 x 10²³ molecules)(0.0366 mole)/(1.0 mole) = 2.2 x 10²² molecules.

3 0

3 years ago

When a cell is in a solution where the concentration of solute is the same in the cell as in the solution, the solution is calle

Elodia [21]

The answer to this question would be: isotonic

An isotonic solution has a same tonicity/concentration to the cell. This kind of solution will not cause osmosis to occur so it wouldn't shrink or swell the cells. This is why an isotonic solution is safer for the cells. The normal saline solution is isotonic to human cells and used frequently in medicine to replace body fluid.

7 0

4 years ago

A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following

marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

$\frac{V_1}{n_1} =\frac{V_2}{n_2}$

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

$\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}$

V₂ = 4,00L

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

$\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}$

V₂ = 16,00L

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

$\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}$

V₂ = 12,31L

I hope it helps!

6 0

4 years ago

Is there a phobia for chemical reactions specifically?

gizmo_the_mogwai [7]

Answer:

chemonoia

Explanation:

Many people have a strong fear of “chemicals” that belies the evidence. It's called chemonoia – and it may be damaging their health. If you were paranoid, you might think there really was something in the water that's damaged our sense of reason.

8 0

3 years ago

Calculate the standard emf for the following reaction:

krek1111 [17]

In order to solve this, we need to know the standard cell potentials of the half reaction from the given overall reaction.
The half reactions with their standard cell potentials are:
2ClO−3(aq) + 12H+(aq) + 10e- = Cl2(g) + 6H2O(l)
E = +1.47

Br(l) + 2e- = 2Br-
E = +1.065

We solve for the standard emf by subtracting the standard emf of the oxidation from the reducation, so:
1.47 - 1.065 = 0.405 V

4 0

3 years ago