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Nadusha1986 [10]
3 years ago
11

Whats is tge electron configuration of Ag2+ please answer asap..

Chemistry
1 answer:
Triss [41]3 years ago
6 0

Answer:

1s2  2s2  2p6  3s2  3p6  3d10 4s2  4p6  4d10

Explanation:

To write the configuration for the Silver and the Silver ion, first we need to write the electron configuration for just Silver (Ag).  We first need to find the number of electrons for the Ag atom (there are 47 electrons) using the Periodic Table.   When we write the configuration, we'll put all 47

Either way,  the Silver  electron configuration will be 1s2  2s2  2p6  3s2  3p6  3d10 4s2  4p6  4d10  5s1    

Note that when writing the electron configuration for an atom like Ag and Ag+, the 4d is usually written before the 5s.   Both of the configurations have the correct numbers of electrons in each orbital, it is just a matter of how the electronic configuration notation is written (see below for an explanation why).

For the Ag+, called the Silver ion,  we remove one electron from 5s2 leaving us with:

1s2  2s2  2p6  3s2  3p6  3d10 4s2  4p6  4d10

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a sample of gold required 2.1200j of heat to melt it from room temperature, 22.0 degrees celsius to its melting point, 1064.4 de
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⇒ 4.1477228099

The amount of heat(q) required to raise m grams of a substance-specific C from T1 to T2 is given by

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Given : q= 2.1200 J

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1 year ago
A sample was prepared by mixing 18. ml of 3.00 x 10^-3 m crystal violet (cv) with 2.00 ml of 0.250 m naoh. calculate the resulti
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Answer : The resulting concentrations of CV and NaOH are 0.0027 M and 0.025 M respectively.

Explanation :

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The volume of crystal violet solution is 18 mL which is 0.018 L.

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NaOH (aq) \rightarrow Na^{+} (aq) + OH^{-} (aq)

The mole ratio of NaOH and OH⁻ is 1:1 . Therefore the concentration of OH⁻ is same as that of NaOH.

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