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Nadusha1986 [10]
3 years ago
11

Whats is tge electron configuration of Ag2+ please answer asap..

Chemistry
1 answer:
Triss [41]3 years ago
6 0

Answer:

1s2  2s2  2p6  3s2  3p6  3d10 4s2  4p6  4d10

Explanation:

To write the configuration for the Silver and the Silver ion, first we need to write the electron configuration for just Silver (Ag).  We first need to find the number of electrons for the Ag atom (there are 47 electrons) using the Periodic Table.   When we write the configuration, we'll put all 47

Either way,  the Silver  electron configuration will be 1s2  2s2  2p6  3s2  3p6  3d10 4s2  4p6  4d10  5s1    

Note that when writing the electron configuration for an atom like Ag and Ag+, the 4d is usually written before the 5s.   Both of the configurations have the correct numbers of electrons in each orbital, it is just a matter of how the electronic configuration notation is written (see below for an explanation why).

For the Ag+, called the Silver ion,  we remove one electron from 5s2 leaving us with:

1s2  2s2  2p6  3s2  3p6  3d10 4s2  4p6  4d10

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Mars2501 [29]

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3 years ago
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Calculate the number of gold atoms in a sample of gold(III) chloride . Be sure your answer has a unit symbol if necessary, and r
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Answer: N = 2.78 × 10^23 atoms

There are N = 2.78 × 10^23 atoms in 70g of Au2cl6

Completed Question:

Calculate the number of gold atoms in a 70g sample of gold(III) chloride . Be sure your answer has a unit symbol if necessary, and round it to significant digits

Explanation:

Given:

Molar mass of Au2cl6 = 303.33g/mol

Mass of Au2cl6 = 70g

Number of moles of Au2cl6 = 70g/303.33g/mol = 0.231mol

According to the chemical formula of Au2cl6,

1 mole of Au2cl6 contains 2 moles of Au

Number of moles of Au = 2 × 0.231mol = 0.462mole

There are 6.022 × 10^23 atoms in 1 mole of an element.

Number of Atom of gold in 0.462 mole of gold is:

N = 0.462 mol × 6.022 × 10^23 atoms/mol

N = 2.78 × 10^23 atoms

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