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Setler79 [48]
3 years ago
5

Why do scientist use models to study atoms

Chemistry
2 answers:
maxonik [38]3 years ago
6 0

Scientist use models to study atoms because you cannot either see or perceive directly what do atoms look like.

Models permit to explain in a simplified way how the atoms are constituted, and, so, figure out how they behave and how they are the bulding blocks of the matter (elements and compounds).

A model can be a drawing or structure with balls and sticks, which show in an idealized way what an atom is.

Since the scientists have discovered different facts about the atoms along the last 200 years the models of the atoms have also evolved.

The plum pudding model of the atom proposed by JJ Thompson was different of the nuclear model proposed by Rutherford, and Rutherford's was different from the planetary model proposed by Bohr, and this is different from the quantum model.


lesya [120]3 years ago
4 0
Models are used to study atoms because we can never really see an atom up close, and a model is like a super magnified version of the atom. Plus, its easier to study from them because we can pin point the different characteristics of the atom (Protons, Neutrons, etc.)
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hjlf

The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)

Suppose 1.20 mol CS_2(g) of and 3.60 mol of Cl_2(g)  were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol  of CCl_4. Calculate equilibrium constant at the unknown temperature.

Answer: The equilibrium constant at unknown temperature is 0.36

Explanation:

Moles of  CS_2 = 1.20 mole

Moles of  Cl_2 = 3.60 mole

Volume of solution = 1.00  L

Initial concentration of CS_2 = \frac{moles}{volume}=\frac{1.20mol}{1L}=1.20M

Initial concentration of Cl_2 = \frac{moles}{volume}=\frac{3.60mol}{1L}=3.60M

The given balanced equilibrium reaction is,

                 CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)

Initial conc.         1.20 M        3.60 M                  0                  0

At eqm. conc.     (1.20-x) M   (3.60-3x) M   (x) M        (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}

Now put all the given values in this expression, we get :

K_c=\frac{(x)\times (x)}{(3.60-3x)^3\times (1.20-x)}

Given :Equilibrium concentration of CCl_4 , x = \frac{moles}{volume}=\frac{0.72mol}{1L}=0.72M

K_c=\frac{(0.72)\times (0.72)}{(3.60-3\times 0.72)^3\times (1.20-0.72)}

K_c=0.36

Thus equilibrium constant at unknown temperature is 0.36

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Given that a 12.00 g milk chocolate bar contains 8.000 g of sugar, calculate the percentage of sugar present in 12.00 g of milk
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Answer:

See explanation

Explanation:

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Note that the BH2 and H adds to the two atoms of the double bond. The final product of the reaction appears as if water was added to the original alkene following an anti-Markovnikov mechanism.

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