The third graphic system shares the same set of solutions.
Notice that the first graph is two parallel lines that never cut.
The second graph has two lines that intersect at a point. Therefore, compare a single solution.
The third graph shares the whole set of solutions since, for each x, both lines take the same Y value
answer
Third graphic.
{5+2b+3c=0
5−2b+c=0
adding both equations u get10+4c=0⇒c=−10/4=−5/2
then5−2b+(−5/2)=0⇒b=(5/2−5)/(−2)=5/2−5/4=5/4
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Hello from MrBillDoesMath!
Answer:
5
Discussion:
Consider the expansion of e^x:
e^x = 1 + x + x^2/2 + x^3/6 +...... => replace x by 5t
e^(5t) = 1 + (5t) + (5t)^2/2 + .... => subtract 1 from both sides
e^(5t) - 1 = (5t) + (5t)^2/2+.... => divide both sides by t
(e^(5t) -1)/ t = 5 + (25/2) t +....
so as t ends to 0 the quotient tends to
5 + (25/2)0 + (other terms) *0 -> 5
Thank you,
MrB
Answer:
y = - 17/3
Step-by-step explanation:
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