Answer:
B) -2
Step-by-step explanation:
I got the slope by using two points on the line (0,7) and (4,-1)
Slope=y2-y1/x2-x1
(7--1)/(0-4)
=
8/-4
I then simplified 8/-4 to -2
You could also solve by finding the rise over run for two points on the line.
The rise is 2 and the run is -1, making it 2/-1 or -2
<span>A system of equations has infinitely many solutions when the two
lines representing the equations coincide. i.e. the two equations are
the same or a multiple of each other.
2y - 4x = 6
2y = 4x + 6
2y = 2(2x + 3)
y = 2x + 3
-y = -(2x + 3)
-y = -2x - 3
Hence the other equation is -y = -2x - 3</span>
The answer would be C)3-x/x(x-1)
Answer:
δL/δt = 634,38 ft/s
Step-by-step explanation:
A right triangle is shaped by ( y = distance between aircraft and ground which is constant and equal to 405 f ) a person who is at ground level 3040 f away from the tower distance x = 3040 f and the line between the aircraft and the person. Then we can use Pythagoras theorem and write
L ( distance between aircraft and person )
L² = x² + y² or L² = x² + (405)²
Taken partial derivatives with respect to t we get:
2*L*δL/δt = 2*x*δx/t + 0
Then L*δL/δt = x*δx/dt
At the moment of the aircraft passing over the tower
x = 3040 ft δx/δt = 640 ft/s and L = √ ( 3040)² + (405)²
So L = √9241600 + 164025 L = √9405625 L ≈3066,9 ft
Then:
δL/δt = 3040*640/ 3066,9 units [ ft * ft/s / ft ] ft/s
δL/δt = 634,38 ft/s
