Answer:
184.43in².
Step-by-step explanation:
Total surface area of the solid = volume of the cube - the volume of the cone
For the CUBE;
Volume of the cube = L³ where L is the length of one side of the cube.
Since a cone of diameter of 6in is cut into a cube, then the length of the cube will be 6in.
Volume of the cube = 6³ = 216in³
For the CONE;
Volume of the cone = 1/3 πr²h
r is the radius of the cone = diameter/2
r = 6/2 = 3in
slant height l = 4.5in
the height h of the cone will be derived using the Pythagoras theorem.
l² = h²+r²
4.5² = h²+3²
h² = 4.5²-3²
h² = 11.25
h=√11.25
h = 3.35in
Volume of the cone = 1/3 × π × 3²× 3.35
= 31.57in³
Total surface area of the solid = 216in³-31.57in³
= 184.43in²
Answer:
(-3,2)
Step-by-step explanation:
Answer:
Volume of cylinder is 6285.71 square units.
Step-by-step explanation:
Given the radius of cylinder 10 units. The height is twice its radius. we have to find its volume.
r=10 units
⇒ Diameter, d = 20 units
Also given height is twice its radius.
⇒ Height=2(r)=2(10)=20 units
<h2><em><u>Volume of cylinder=πr^2h</u></em></h2>
= 22/7 × 100×20
=22/7 × 2000
= 44000/7
= 6285.71square units.
hence, volume of cylinder is 6285.71 square units.
Answer:
25%
Step-by-step explanation:
100%-30%=70%
70%-45%=25%
Answer:
The third option listed: ![\sqrt[3]{2x} -6\sqrt[3]{x}\\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x%7D%20-6%5Csqrt%5B3%5D%7Bx%7D%5C%5C)
Step-by-step explanation:
We start by writing all the numerical factors inside the qubic roots in factor form (and if possible with exponent 3 so as to easily identify what can be extracted from the root):
![7\sqrt[3]{2x} -3\sqrt[3]{16x} -3\sqrt[3]{8x} =\\=7\sqrt[3]{2x} -3\sqrt[3]{2^32x} -3\sqrt[3]{2^3x} =\\=7\sqrt[3]{2x} -3*2\sqrt[3]{2x} -3*2\sqrt[3]{x}=\\=7\sqrt[3]{2x} -6\sqrt[3]{2x} -6\sqrt[3]{x}](https://tex.z-dn.net/?f=7%5Csqrt%5B3%5D%7B2x%7D%20%20-3%5Csqrt%5B3%5D%7B16x%7D%20-3%5Csqrt%5B3%5D%7B8x%7D%20%3D%5C%5C%3D7%5Csqrt%5B3%5D%7B2x%7D%20%20-3%5Csqrt%5B3%5D%7B2%5E32x%7D%20-3%5Csqrt%5B3%5D%7B2%5E3x%7D%20%3D%5C%5C%3D7%5Csqrt%5B3%5D%7B2x%7D%20%20-3%2A2%5Csqrt%5B3%5D%7B2x%7D%20-3%2A2%5Csqrt%5B3%5D%7Bx%7D%3D%5C%5C%3D7%5Csqrt%5B3%5D%7B2x%7D%20%20-6%5Csqrt%5B3%5D%7B2x%7D%20-6%5Csqrt%5B3%5D%7Bx%7D)
And now we combine all like terms (notice that the only two terms we can combine are the first two, which contain the exact same radical form:
![7\sqrt[3]{2x} -6\sqrt[3]{2x} -6\sqrt[3]{x}=\\=\sqrt[3]{2x} -6\sqrt[3]{x}](https://tex.z-dn.net/?f=7%5Csqrt%5B3%5D%7B2x%7D%20%20-6%5Csqrt%5B3%5D%7B2x%7D%20-6%5Csqrt%5B3%5D%7Bx%7D%3D%5C%5C%3D%5Csqrt%5B3%5D%7B2x%7D%20-6%5Csqrt%5B3%5D%7Bx%7D)
Therefore this is the simplified radical expression:
