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love history [14]
3 years ago
7

If you have 100 grams of different substances, the LEAST dense substance would have which volume?

Physics
1 answer:
Vera_Pavlovna [14]3 years ago
4 0

0.10 L or d as a letter

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krek1111 [17]

Explanation:

the table and the wooden block

6 0
3 years ago
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What wave on the electromagnetic spectrum has the highest frequency?
Jet001 [13]

Answer:

Explanation:

Answer: Gamma rays

Gamma rays have the highest frequency.

What is an electromagnetic wave?

An electromagnetic wave requires no medium for its propagation.

It consists of a spectrum of different wavelengths.

Different wavelengths of rays have different energies and different frequencies.

Higher frequency rays have the highest energies.

What is gamma-ray?

These are ionized radiations.

Gamma radiations are obtained from the decay of the atomic nucleus.

It has the highest frequency which is why it can penetrate through matter.

It has the smallest wavelength and highest energy.

The frequency of gamma rays is more than 10^19 cycles per second and wavelength less than 100 picometers.

6 0
2 years ago
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The 2.50 kg cube in the figure has edge lengths d = 6.50 cm and is mounted on an axle
kozerog [31]

Answer:

0.191 s

Explanation:

The distance from the center of the cube to the upper corner is r = d/√2.

When the cube is rotated an angle θ, the spring is stretched a distance of r sin θ.  The new vertical distance from the center to the corner is r cos θ.

Sum of the torques:

∑τ = Iα

Fr cos θ = Iα

(k r sin θ) r cos θ = Iα

kr² sin θ cos θ = Iα

k (d²/2) sin θ cos θ = Iα

For a cube rotating about its center, I = ⅙ md².

k (d²/2) sin θ cos θ = ⅙ md² α

3k sin θ cos θ = mα

3/2 k sin(2θ) = mα

For small values of θ, sin θ ≈ θ.

3/2 k (2θ) = mα

α = (3k/m) θ

d²θ/dt² = (3k/m) θ

For this differential equation, the coefficient is the square of the angular frequency, ω².

ω² = 3k/m

ω = √(3k/m)

The period is:

T = 2π / ω

T = 2π √(m/(3k))

Given m = 2.50 kg and k = 900 N/m:

T = 2π √(2.50 kg / (3 × 900 N/m))

T = 0.191 s

The period is 0.191 seconds.

7 0
3 years ago
A 5-m steel beam is lowered by means of two cables unwinding at the same speed from overhead cranes. As the beam approaches the
ArbitrLikvidat [17]

Answer:

a) The angular acceleration of the beam is 0.5 rad/s²CW (direction clockwise due the tangential acceleration is positive)

b) The acceleration of point A is 3.25 m/s²

The acceleration of point E is 0.75 m/s²

Explanation:

a) The relative acceleration of B with respect to D is equal:

a_{B} =a_{D} +(a_{B/D} )_{n} +(a_{B/D} )_{t}

Where

aB = absolute acceleration of point B = 2.5 j (m/s²)

aD = absolute acceleration of point D = 1.5 j (m/s²)

(aB/D)n = relative acceleration of point B respect to D (normal direction BD) = 0, no angular velocity of the beam

(aB/D)t = relative acceleration of point B respect to D (tangential direction BD)

a_{B} =a_{D}  +(a_{B/D} )_{t}

2.5j=1.5j  +(a_{B/D} )_{t}\\(a_{B/D} )_{t}=j=1m/s^{2}

We have that

(aB/D)t = BDα

Where α = acceleration of the beam

BDα = 1 m/s²

Where

BD = 2

2\alpha =1\\\alpha =0.5rad/s^{2}CW

b) The acceleration of point A is:

a_{A} =a_{D}  +(a_{A/D} )_{t}

(aA/D)t = ADαj

a_{A} =a_{D}  +AD\alpha j\\a_{A}=1.5j+(3.5*0.5)j\\a_{A}=3.25jm/s^{2}

The acceleration of point E is:

(aE/D)t = -EDαj

a_{E} =a_{D}  -ED\alpha j\\a_{E}=1.5j-(1.5*0.5)j\\a_{E}=0.75jm/s^{2}

7 0
3 years ago
Which tool would you use to measure the amount of rainfall? a. graduated cylinder b. stopwatch c. scale d. thermometer
Fittoniya [83]

A graduated cylinder measures the volume of a liquid.

A stopwatch measures the amount of time that elapses.

A scale measures the mass of objects.

A thermometer measures the temperature of any object.

Because we are measuring rain, a liquid, we would want to use a tool that would allow us to collect the rain for measuring. Therefore, the tool e would use to measure the amount of rainfall would be A. a graduated cylinder.

5 0
3 years ago
Read 2 more answers
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