Answer:
Explanation:
initial velocity, u = 8 m/s
vertical height, h = 1 m
θ = 40°
Let the horizontal distance is d and the time taken is t.
Use second equation of motion in vertical direction
h = ut + 1/2 at²
1 = 8 Sin 40 x t + 0.5 x 9.8 t²
1 = 5.14 t - 4.9t²
4.9t² - 5.14 t + 1 = 0
so, t = 0.26 s (smaller value)
So, the horizontal distance is
d = u cos 40 x t
d = 8 cos 40 x 0.26
d = 1.6 m
Meters for mass kilograms for volume cubic meters for density kilograms per cubic meter
The current in the wire has created a magnetic field with its north pole at the top of the rod. A magnetic field influences electric currents.
<h3>What is a magnetic field?</h3>
A magnetic field is a type of field that influences the position and direction of the electric current.
The magnetic field also refers to the one where magnetic forces act to shape an electrical current.
The only material and/or body capable of altering an electrical current in a magnetic field is the presence of another magnetic field.
Learn more about magnetic fields here:
brainly.com/question/14411049
Answer:
R1 + R2 = R = 12 for resistors in series - so R1 = R2 if they are identical
2 R1 = 12 and R1 = R2 = 6 ohms
1 / R = 1 / R1 + 1 / R2 for resistors in parallel
R = R1 * R2 / (R1 + R2) = 6 * 6 / (6 + 6) = 3
The equivalent resistance would be 3 ohms if connected in parallel
Answer:
u = 104.68 m/s
Explanation:
given,
horizontal distance = 150 m
elevation of 12.4 m
angle = 8.6°
horizontal motion = x = u cos θ. t .............(1)
vertical motion =
................(2)
from equation(1) and (2)
..........{3}
![12.4 = 150\times tan (8.6) - \dfrac{9.8\times 150^2}{2u^2cos^2(8.6)}](https://tex.z-dn.net/?f=12.4%20%3D%20150%5Ctimes%20tan%20%288.6%29%20-%20%5Cdfrac%7B9.8%5Ctimes%20150%5E2%7D%7B2u%5E2cos%5E2%288.6%29%7D)
![\dfrac{9.8\times 150^2}{2u^2cos^2(8.6)} = 10.29](https://tex.z-dn.net/?f=%5Cdfrac%7B9.8%5Ctimes%20150%5E2%7D%7B2u%5E2cos%5E2%288.6%29%7D%20%3D%2010.29)
![\dfrac{9.8\times 150^2}{2\times 10.29\times cos^2(8.6)} = u^2](https://tex.z-dn.net/?f=%5Cdfrac%7B9.8%5Ctimes%20150%5E2%7D%7B2%5Ctimes%2010.29%5Ctimes%20cos%5E2%288.6%29%7D%20%3D%20u%5E2)
![u = \sqrt{10959.34}](https://tex.z-dn.net/?f=u%20%3D%20%5Csqrt%7B10959.34%7D)
u = 104.68 m/s
The initial speed of the ball is u = 104.68 m/s