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kenny6666 [7]
3 years ago
5

In a football game, running back is at the 10 yard line and running up the field towards the 50 yard line, and runs for 3 second

s at 8yd/s. what is his current position(in yards)?
Physics
1 answer:
lakkis [162]3 years ago
7 0
If he keeps that pace he will be at the 34 yard line
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A charged particle is moving in a uniform magnetic field at a speed of 8.2Ã10^3 m/s in a direction 87° from the direction of th
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Answer:

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Explanation:

It is given that,

Speed of charged particle, v=8.2\times 10^3\ m/s

Angle between velocity and the magnetic field, \theta=87

Charge, q=5.7\ \mu C=5.7\times 10^{-6}\ C

Magnetic force, F = 0.002 N

The magnetic force is given by :

F=qvB\ sin\theta

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B=\dfrac{F}{qv\ sin\theta}

B=\dfrac{0.002}{5.7\times 10^{-6}\times 8.2\times 10^3\times sin(87)}

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