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2 years ago

5

In a football game, running back is at the 10 yard line and running up the field towards the 50 yard line, and runs for 3 second

s at 8yd/s. what is his current position（in yards）?

1 answer:

lakkis [162]2 years ago

7 0

If he keeps that pace he will be at the 34 yard line

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John throws a baseball from a standing position. Which of the three possible paths will the ball follow?

Marysya12 [62]

Answer: C

Explanation:

Bro this is common sense. Throw something across the room and watch it. It isnt going to be repulsed and fly up. It also isnt going to continue on forever. It will clearly fall and hit the ground

3 0

3 years ago

Read 2 more answers

A box of volume V has a movable partition separating it into two compartments. The left compartment contains 3000 particles, the

storchak [24]

Answer:

a) V1 = 4V - V2/3 and V2 = 4V - 3V1

b) Δe = 4000V - 4000V2 + 9000V1

Explanation:

Let V represent volume of the box containing the two compartments

V1 represents compartment of the left compartment

V2 represents compartment of the right compartment

Momentum of the compartments before impact:

3000V1 + 1000V2

Momentum of the compartments after impact:

V(3000 + 1000) = 4000V

a) To obtain the volume of each compartment, that is, V1 and V2, we say:

Momentum before impact = Momentum after impact

3000V1 + 1000V2 = 4000V

∴ V1 = 4000V - 1000V2/3000 = 4V - V2/3

Also, V2 = 4000V - 3000V1/1000 = 4V - 3V1

b) Change in entropy,Δe = 4000V1 - 1000V2

By substituting the V1 and V2, we have:

4000(4V - V2)/3 - 1000(4V - 3V1)

16000V - 4000V2/3 - 4000V + 3000V1

16000V - 4000V2 - 12000V + 9000V1

∴ Δe = 4000V - 4000V2 + 9000V1

6 0

3 years ago

Technician A says that side post terminals need to be removed to inspect them for corrosion. Technician B says that side post te

zlopas [31]

Answer: C

Explanation: Side post terminals need to be removed to inspect them for corrosion.

Over tightening the terminal bolt can damage side post terminals.

The battery terminals and cable ends can corrode especially when the battery or car is not used for a long period of time. Corrosion limits a battery's lifespan and so should be prevented. To inspect the areas where corrosion occur on a side-post battery, you need to remove the terminals.

Also, it is true that over tightening the terminal bolt can damage the side post terminals. The covering on the battery can become twisted, and make the seals on the terminals leak.

4 0

3 years ago

Starting from rest, a 2.1x10^-4 kg flea springs straight upward. While the flea is pushing off from the ground, the ground exert

Rainbow [258]

Answer:

a) The flea's speed when it leaves the ground is $v=1.88m/s$

b) The flea move $18cm$ upward while it is pushing off

Explanation:

Hi

<u>Knwons</u>

Mass $m=2.1\times 10^{-4} kg$ , Work $W=3.7\times 10^{-4} J$ and Force $F=0.41N$

a) Here we are going to use $W=\frac{1}{2} mv^{2}$ , so $v=\sqrt{\frac{2W}{m} }= \sqrt{\frac{2(3.7\times 10^{-4} J)}{2.1\times 10^{-4} kg} }=1.88m/s$

a) Here we are going to use $W=mgh$ , so $h=\frac{W}{mg}= \frac{3.7\times 10^{-4} J}{(2.1\times 10^{-4} kg)(9.8m/s^{2})} =0,1797m$ or $18cm$ approx.

7 0

3 years ago

Light from a 560 nm monochromatic source is incident upon the surface of fused quartz (n=1. 56) at an angle of 60°. what is the

ankoles [38]

The angle of reflection is "60°".

Here we apply the law of the concept of reflection then we get the final answer easily.

The angle of incident = angle of reflection

Then, the Angle of the incident =60°

What is reflection?

Reflection is the phenomenon of light rays returning to the source after striking an obstruction.
It resembles the way a ball bounces when we toss it on a hard surface.
Some of the light rays that strike an item are reflected, some of them travel through it, and the remainder are absorbed by the object.
The given values are:Light from a monochromatic source,= 560 nm
The angle of incidence,= 60°
The surface of fused quartz (n),= 1.56
When a light ray does exist on a flat surface, the law or idea of reflection should apply since it includes both the reflected and "normal" light rays at the mirror surface.
According to the above law,Angle of incident = angle of reflection
Then, Angle of incident =60°.

To learn more about reflection visit: brainly.com/question/15487308

#SPJ4

7 0

1 year ago