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3 years ago

What is the relationship between "friction" and "thermal energy?"

1 answer:

4 0

When temperature increases, particles in an object speed up, which means an increase in thermal energy. Since the particles are moving more now, the potential energy decreases, therefore kinetic energy increases. Overall,when temperature go up, thermal energy go up, which leads to an increase to kinetic energy.

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A mass on a spring oscillates with a period T. Part A If both the mass and the force constant of the spring are doubled, the new

garik1379 [7]

Answer:

The new time period will be T.

Explanation:

The time period in terms of spring constant and mass is given by :

$T=2\pi\sqrt{\dfrac{m}{k}}$

If mass and force constant is doubled, m' = 2m and k' = 2k

New time period is given by :

$T'=2\pi\sqrt{\dfrac{m'}{k'}}$

$T'=2\pi\sqrt{\dfrac{2m}{2k}}$

$T'=2\pi\sqrt{\dfrac{m}{k}}$

$T'=T$

So, the new period will remains the same. Hence, the correct option is (C).

4 0

3 years ago

In certain ranges of a piano keyboard, more than one string is tuned to the same note to provide extra loudness. For example, th

diamong [38]

Answer:

3.77 Hz

Explanation:

The beat frequency that is heard can be calculated using the following equation:

$f_{b} = f_{1} - f_{2}$

Where:

f₁ = 110 Hz

$f_{2} = \frac{f_{1}}{\sqrt{\frac{T_{1}}{T_{2}}}}$

With:

T₁ = 594 N

T₂ = 554 N

$f_{2} = \frac{f_{1}}{\sqrt{\frac{T_{1}}{T_{2}}}} = \frac{110 Hz}{\sqrt{\frac{594 N}{554 N}}} = 106.23 Hz$

Hence, the beat frequency is:

$f_{b} = f_{1} - f_{2} = 110 Hz - 106.23 Hz = 3.77 Hz$

Therefore, the beat frequency that is heard when the hammer strikes the two strings simultaneously is 3.77 Hz.

I hope it helps you!

3 0

4 years ago

An object initially at rest breaks into two pieces as the result of an explosion. One piece has twice the energy of the other pi

Butoxors [25]

M₁V₁ = m₂V₂
KE = ½mV² 
½m₁V₁² = 2*½m₂V₂² 

m₁V₁ = m₂V₂ 
½m₁V₁² = m₂V₂² 

m₁/m₂ = V₂/V₁ 

m₁/m₂ = 2V₂²/V₁² 
V₂/V₁ = √(½m₁/m₂) 

m₁/m₂ = √(½m₁/m₂) 
squaring
(m₁/m₂)² = ½m₁/m₂ 

2m₂m₁² = m₁m₂² 
divide by m₁m₂ 
2m₁ = m₂ 
m₂/m₁ = 2
hope this helps

4 0

4 years ago

An aluminum wire having a cross-sectional area equal to 3.90 10-6 m2 carries a current of 6.00 A. The density of aluminum is 2.7

stich3 [128]

Answer:

Vd = 1.597 ×10⁻⁴ m/s

Explanation:

Given: A = 3.90×10⁻⁶ m², I = 6.00 A, ρ = 2.70 g/cm³

To find:

Drift Velocity Vd=?

Solution:

the formula is Vd = I/nqA (n is the number of charge per unit volume)

n = No. of electron in a mole ( Avogadro's No.) / Volume

Volume = Molar mass / density ( molar mass of Al =27 g)

V = 27 g / 2.70 g/cm³ = 10 cm³ = 1 × 10 ⁻⁵ m³

n= (6.02 × 10 ²³) / (1 × 10 ⁻⁵ m³)

n= 6.02 × 10 ²⁸

Now

Vd = (6A) / ( 6.02 × 10 ²⁸ × 1.6 × 10⁻¹⁹ C × 3.9×10⁻⁶ m²)

Vd = 1.597 ×10⁻⁴ m/s

6 0

3 years ago

1) how can you show that atmospheric exerts pressure?

Kruka [31]

Answer:

1. While boiling replace the cap and allow it to cool. Vapours inside condense and form water creating vacuum above them. Observation - The can crumbles due to air pressure from outside. This proves that air exerts pressure.

2. Measure the volume of the liquid displaced when the object is submerged. Measure the initial volume of water in graduated cylinder. Submerge the irregular object. Measure the final volume of the water.

— The difference between the initial volume and the final volume is the volume of the object.

hope can help ^_^

7 0

3 years ago