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3 years ago

8

What is the relationship between "friction" and "thermal energy?"

1 answer:

SCORPION-xisa [38]3 years ago

4 0

When temperature increases, particles in an object speed up, which means an increase in thermal energy<span>. Since the particles are moving more now, the potential energy decreases, therefore kinetic energy increases. Overall,when temperature go up, thermal energy go up, which leads to an increase to kinetic energy.</span>

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Help asap please thank you

Tom [10]

Answer:

the answer its time

v = d/t

8 0

3 years ago

Read 2 more answers

If 270 watts of power is used in 42 seconds, how much work was done<br>

navik [9.2K]

Answer: W = 11340J

Explanation:

Hey there! I will give the following steps, if you have any questions feel free to ask me in the comments below.

So this is the Formula: Power = Work / Time.

<u>Step 1:</u><em><u> Find the Formula</u></em>

P = W / T

<em><u> </u></em>

<u>Step 2: </u><u><em>Make W the subject of the equation.</em></u>

W = PT

<u>Step 3:</u><u> </u><u><em>Given.</em></u>

P = 270 Watts, T = 42 seconds

<u>Step 4:</u><u><em> Substitute these values into equation 2 .</em></u>

W = 270(42)

<u>Step 5:</u><u> </u><u><em>Simplify.</em></u>

W = 11340J

The amount of work done was 11340.

~I hope I helped you! :)~

4 0

4 years ago

If oxygen and steel wool are combined is it a physical change or chemical change?

Anon25 [30]

Answer:

I think it would be a chemical change.

Explanation:

Because a physical would be like crushing it or something along that line.

4 0

3 years ago

Read 2 more answers

Which of the following situations is an example of kinetic energy being transformed into potential energy? Throwing a ball high

motikmotik

Answer: holding the ball in the air without moving it

Explanation:

When the ball goes up it’s potential energy

6 0

3 years ago

A ski jumper travels down a slope and

AleksandrR [38]

Answer:

304.86 metres

Explanation:

The x and y cordinates are $dcos\theta$ and $dsin\theta$ respectively

The horizontal distance travelled, $x=v_{ox}t=dcos\theta$

Making t the subject, $t=\frac{dcos\theta}{v_{ox}}$

Since $y=0.5gt^2=dsin\theta$ , we substitute t with the above and obtain

$0.5g(\frac{dcos\theta}{v_{ox}})^2=dsin\theta$

Making d the subject we obtain

$d=\frac{2v_{ox}^2sin\theta}{gcos^2\theta}$

$d=\frac{2*30^2sin48}{9.8cos^248}$

d=304.8584

d=304.86m

5 0

3 years ago