Three remote control cars are identical size and weight. The motors installed in the three cars are 100 watts, 150 watts and 200
1 answer:
Answer:
The true statement about the maximum speed of each car will be that the power of each car directly proportional to the speed of each car.
Explanation:
Given that,
Power of first car = 100 watt
Power of second car = 150 watt
Power of third car = 200 watt
We know that,
Power :
The power is directly proportional to the cube of speed.
In mathematically,
Where, P = power
v = speed
If the power is increased then the speed will be increase.
We need to find the maximum speed of car
According to question,
The power of car is maximum so the speed of car will be maximum.
For first car,
The power of first car is 100 watt.
So, the speed of first car will be 1000000 m/s.
For second car,
The power of second car is 150 watt.
So, the speed of second car will be 3375000 m/s.
For third car,
The power of third car is 200 watt.
So, the speed of first car will be 8000000 m/s.
Hence, The true statement about the maximum speed of each car will be that the power of each car directly proportional to the cube of speed of each car.
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Answer:
that best describes the process is C
Explanation:
This problem is a calorimeter process where the heat given off by one body is equal to the heat absorbed by the other.
Heat absorbed by the smallest container
Q_c = m ce (-T₀)
Heat released by the largest container is
Q_a = M ce (T_{i}-T_{f})
how
Q_c = Q_a
m (T_{f}-T₀) = M (T_{i} - T_{f})
Therefore, we see that the smaller container has less thermal energy and when placed in contact with the larger one, it absorbs part of the heat from it until the thermal energy of the two containers is the same.
Of the final statements, the one that best describes the process is C
since it talks about the thermal energy and the heat that is transferred in the process
Answer:
The velocity of the plane at take off is 160 m/s.
The distance travel by the plane in that time is 3200 meter.
Explanation:
Given:
Acceleration, a = 4 m/s²
Time, t = 40 s
u = 0 i .e initial velocity
To Find:
velocity , v = ?
distance , s =?
Solution:
we have first Kinematic equation
v = u + at
∴ v = 0 + 4×40
∴ v = 160 m/s
Now by Third Kinematic equation
∴ s = 0 + 0.5 × 4× 40²
∴ s = 3200 meter