Can you post a picture of the whole thing please
Answer:
speed when it reaches y = 4.00cm is
v = 14.9 g.m/s
Explanation:
given
q₁=q₂ =2.00 ×10⁻⁶
distance along x = 3.00cm= 3×10⁻²
q₃= 4×10⁻⁶C
mass= 10×10 ⁻³g
distance along y = 4×10⁻²m
r₁ = 
= 
= 3.61cm = 0.036m
r₂ = 
= 
= 5cm = 0.05m
electric potential V = 
change in potential ΔV = 
ΔV = 
, where 
2.00μC
ΔV = 
ΔV = 2 × 9×10⁹ × 2×10⁻⁶ × 
ΔV= 2.789×10⁵
= ΔV × q₃
ˣ 10×10⁻³ ×v² = 2.789×10⁵× 4 ×10⁻⁶
v² = 223.12 g.m/s
v = 14.9 g.m/s
Flood plain, meanders, Qxbow lake, valley, and waterfalls!!!!
The percentage error in calculated value of the refractive index of acrylic block is calculated using the formula: (true value - calculated value/true value) × 100%.
<h3>What is refractive index of a refracting medium?</h3>
The refractive index of a medium is the ratio of the sine of the angle of incidence on the medium and the sine of the angle of refraction.
- Refractive index = sin i/sin r
where;
- i is the angle of incidence
- r is angle of refraction.
The refractive index of a medium increases with density of the medium.
To determine the percentage error in determining the refractive index of a medium, the following formula is used:
- Percent error = error/true value × 100%
Therefore, the percentage error in calculated value of the refractive index of acrylic block is the ratio of the error and true value multiplied by 100%.
Learn more about refractive index at: brainly.com/question/83184
