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1 year ago

Leg 1 Swimming

Physics

1 answer:

OverLord2011 [107]1 year ago

3 0

Answer:

ur blind not deaf u can still talk aey that one day was out violition

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In order for a length of copper wire or a loop of copper wire to have a magnetic field, what must they have flowing through them

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Electricity.
When electricity flows through wire (such as a battery circuit) it creates a magnetic field around the wire.

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3 years ago

Unpolarized light passes through three polarizing filters. The first one is oriented with a horizontal transmission axis, the se

Xelga [282]

Answer:

10.028%

Explanation:

$\theta$ = Angle between polarizer

The polarized light after passing through first polarizer

$I=\frac{I_0}{2}$

The polarized light after passing through second polarizer

$I_2=\frac{I_0}{2}cos^2\theta\\\Rightarrow I_2=\frac{I_0}{2}cos^231.8\\\Rightarrow I_2=0.36115I_0$

The polarized light after passing through third polarizer

$I_3=I_2cos^2(90-31.8)\\\Rightarrow I_3=0.36115I_0cos^2(90-31.8)\\\Rightarrow I_3=0.10028I_0$

$\frac{I_3}{I_0}\times 100=\frac{0.10028I_0}{I_0}\times 100\\ =10.028\ \%$

The percent of the light gets through this combination of filters is 10.028%

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2 years ago

A driven RLC circuit is being driven by an AC emf source with a maximum current of 2.75 A and maximum voltage of 150 V. The curr

weqwewe [10]

Answer:

(a). Z = 54.54 ohm

(b). R = 36 ohm

(c). The circuit will be Capacitive.

Explanation:

Given data

I = 2.75 A

Voltage = 150 V

$\phi = 0.85$ rad = 48.72°

(a). Impedance of the circuit is given by

$Z = \frac{V}{I}$

$Z = \frac{150}{2.75}$

Z = 54.54 ohm

(b). We know that resistance of the circuit is given by

$R = \frac{Z}{\sqrt{1 + \tan^{2}\phi } }$

Put the values of Z & $\phi$ in above formula we get

$R = \frac{54.54}{\sqrt{1 + \tan^{2} ( \ 48.72) } }$

R = 36 ohm

(c). Since the phase angle is negative so the circuit will be Capacitive.

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3 years ago

Manipulate the equation "v=d/t" to find the answers to these problems using

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Yo no me voy a ir a la cama a

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2 years ago

Later, while taking your groceries back to the car, you accidentally let go of your cart. It rolls straight down a grassy slope

VladimirAG [237]

Car is moving on the glassy slope with constant speed

Now we know that

$a = \frac{dv}{dt}$

so acceleration is rate of change in velocity

as we know that velocity is constant here so acceleration is zero

so here

$a = 0$

now as we know by Newton's II law

$F = ma$

since a = 0

$F = 0$

so net force will be ZERO on it during this motion

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3 years ago