Answer:
The current in second wire is 5.0 A.
(B) is correct option.
Explanation:
Given that,
Current in first wire = 3.7 A
Distance = 8.0 cm
We need to calculate the magnetic field due to the current carrying wire
Using formula of magnetic field
Where, I = current
r = distance
Put the value into the formula
For first wire
...(I)
For second wire,
The distance is 8-3.7 = 4.3 cm
...(II)
The magnetic field in both the wires,
From equation (I) and (II)
Hence, The current in second wire is 5.0 A.
Answer:
L = ¼ k g / m
Explanation:
This is an interesting exercise, in the first case the spring bounces under its own weight and in the second it oscillates under its own weight.
The first case angular velocity, spring mass system is
w₁² = k / m
The second case the angular velocity is
w₂² = L / g
They tell us
w₂ = ½ w₁
Let's replace and calculate
√ (L / g) = ½ √ (k / m)
L / g = ¼ k / m
L = ¼ k g / m
Yes, ratio can be expressed in percentage.
Answer:
4.24m/s
Explanation:
Potential energy at the top= kinetic energy at the button
But kinetic energy= sum of linear and rotational kinetic energy of the hoop
PE= mgh
KE= 1/2 mv^2
RE= 1/2 I ω^2
Where
m= mass of the hoop
v= linear velocity
g= acceleration due to gravity
h= height
I= moment of inertia
ω= angular velocity of the hoop.
But
I = m r^2 for hoop and ω = v/r
giving
m g h = 1/2 m v^2 + 1/2 (m r^2) (v^2/r^2) = 1/2 m v^2 + 1/2 m v^2 = m v^2
and m's cancel
g h = v^2
Hence
v= √gh
v= √10×1.8
v= 4.24m/s
Answer:
(B) Resistor only
Explanation:
Alternating Current: These are currents that changes periodically with time.
An LRC Ac circuit is an AC circuit that contains a Resistor, a capacitor and an inductor, connected in series.
In a purely resistive circuit, current and voltage are in phase.
In a purely capacitive circuit, the current leads the voltage by π/2
In a purely inductive circuit, the current lags the voltage by π/2.
Therefore when a alternating current is set up in LRC circuit, in the resistor, the current and the voltage are in phase.
The right option is (B) Resistor only.
