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Stells [14]
2 years ago
12

Leg 1 Swimming

Physics
1 answer:
OverLord2011 [107]2 years ago
3 0

Answer:

ur blind not deaf u can still talk aey that one day was out violition

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Two dogs are pulling on a rope in opposite directions. The dog in the left pulls with a force of 10 N, while the dog in the righ
hodyreva [135]

Answer:

Dog on the right.

Explanation:

Dog on the left is pulling 10N. The dog on the right is pulling at 12N. So the dog on the right is pulling more. Hope this helps :)))

4 0
3 years ago
Read 2 more answers
In 1991 at smith college, in massachusetts, ferdie adoboe ran 1.00 × 102 m backward in 13.6 s. suppose it takes adoboe 2.00 s to
Alik [6]

as it is given that it covers a total distance 1 * 10^2 m

total time taken by it = 13.6 s

now the average speed is given as ratio of total distance and total time

v = \frac{d}{t}

v = \frac{1* 10^2 }{13.6}

v = 7.35 m/s

so the average speed will be 7.35 m/s

now if it starts from rest and achieve the final speed as 7.35 m/s

now we can use kinematics

v_f = v_i + at

7.35 = 0 + a* 2

a = 3.68 m/s^2

so its acceleration will be 3.68 m/s^2

4 0
4 years ago
Forces are measured in Newtons (N). Why are forces considered to be vectors?
prohojiy [21]

Answer:

A force has both magnitude and direction, therefore: Force is a vector quantity; its units are newtons, N. Forces can cause motion; alternatively forces can act to keep (an) object(s) at rest. ... Consider two forces of magnitudes 5 N and 7 N acting on a particle, with an angle of 90◦ between them.

Explanation:

from google

8 0
3 years ago
A toy car has a 1.5-A current, and its resistance is 2 . How much voltage does the car require?
oee [108]

Voltage = (current) x (resistance)

Voltage = (1.5 A) x (2 ohms)

In order to MAKE 1.5 A of current flow through the toy car, you have to PROVIDE <em>3 volts</em> from the battery.

8 0
4 years ago
Read 2 more answers
The vertical motion of mass A is defined by the relation x 5 10 sin 2t 1 15 cos 2t 1 100, where x and t are expressed in millime
nikklg [1K]

Explanation:

Given that,

The vertical motion of mass A is defined by the relation as :

x=10\ sin2t+15\ cos2t+100

At t = 1 s

x=10\ sin2+15\ cos2+100

x = 115.33 mm

(a) We know that,

Velocity, v=\dfrac{dx}{dt}

v=\dfrac{d(10\ sin2t+15\ cos2t+100)}{dt}

v=20\ cos2t-30\ sin2t

At t = 1 s

v=20\ cos2-30\ sin2

v = 18.94 mm/s

We know that,

Acceleration, a=\dfrac{dv}{dt}

a=\dfrac{d(20\ cos2-30\ sin2)}{dt}

a=-40\ cos2t-60\ cos2t

At t = 1 s

v=-40\ cos2-60\ cos2

a=-99.93\ mm/s^2

(b) For maximum velocity, \dfrac{dv}{dt}=a=0

-40\ cos2t-60\ cos2t=0

t = 45 seconds

For maximum acceleration, \dfrac{da}{dt}=0

80\ sin2t+120\ cos2t=0

t = 61.8 seconds

Hence, this is the required solution.

5 0
4 years ago
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