Make a graph and start at the origin (0,0) count down 5 units and across to the right 4 units. Put a dot here. For every 1 unit the line moves to the right, it moves down 3.
Answer:
6-2y=4y+8
since you show x through y
Answer:
The result that is obtained on comparing the system of equations in order to get the solution to the system of equations is:
6 -2y =4y + 8
Step-by-step explanation:
We are given a system of equations in term of variable x and y as follows:
x + 2y = 6 --------(1)
x - 4y = 8-------------(2)
From equation (1) we have the value of x in terms of y as:
x=6-2y
From equation (2) we have the value of x in terms of y as:
x=8+2y
Hence, on equation the above two values of 'x' we obtain:
6 - 2y = 4y + 8
ghope this helps
Answer:
119 R5
divide divide divide divide
16 x 3/8 so 16/1 x 3/8 = 48/8. 48 divided by 8 is 6. So 6 inches.
Answer:
97.98
Step-by-step explanation:
The area of the parallelogram PQR is the magnitude of the cross product of any two adjacent sides. Using PQ and PS as the adjacent sides;
Area of the parallelogram = |PQ×PS|
PQ = Q-P and PS = S-P
Given P(0,0,0), Q(4,-5,3), R(4,-7,1), S(8,-12,4)
PQ = (4,-5,3) - (0,0,0)
PQ = (4,-5,3)
Also, PS = S-P
PS = (8,-12,4)-(0,0,0)
PS = (8,-12,4)
Taking the cross product of both vectors i.e PQ×PS
(4,5,-3)×(8,-12,4)
PQ×PS = (20-36)i - (16-(-24))j + (-48-40)k
PQ×PS = -16i - 40j -88k
|PQ×PS| = √(-16)²+(-40)²+(-88)²
|PQ×PS| = √256+1600+7744
|PQ×PS| = √9600
|PQ×PS| ≈ 97.98
Hence the area of the parallelogram is 97.98
