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3 years ago

Could someone help me with a couple problems relating to quadratic formula? Heres one as an example. 2(12x^2-x)=15.

Mathematics

1 answer:

Gennadij [26K]3 years ago

7 0

Answer:

Step-by-step explanation:

2(12x^2-x)=15

24x^2-2x-15=0

24x^2-20x+18x-15=p

4x(6x-5)+3(6x-5)=0

(4x+3)(6x-5)=0

x= -3/4 or 5/6

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Answer:

x = $3\frac{3}{4}$

Step-by-step explanation:

First, you have to leave 2x by itself on the left side of the equation:

2x = 60/8

Then divide,

x = 15/4

Simplified fraction: x = $3\frac{3}{4}$

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2 years ago

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vovikov84 [41]

Answer:

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3 years ago

Find the domain and range of 1/t+2

kotegsom [21]

Answer:

Domain = (-∞, -2) ∪ (-2, ∞).

Range = (-∞, 0) ∪ (0, ∞).

Step-by-step explanation:

t can't have the value -2 because that would make 1/(t + 2) = 1/0 which is undefined.

So the domain is All real values of t. except t = -2.

As t approaches infinity or negative infinity f(t) approaches zero, and as t approaches -2 from below or above f(t) approaches negative infinity or positive infinity.

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3 years ago

20 points...<br><br> Sherlock - please help!

antiseptic1488 [7]

Answer:

C) $\{\frac{1+\sqrt{5}}{3},\:\frac{1-\sqrt{5}}{3}\}$

Step-by-step explanation:

$(3x-1)^2=5\\\\3x-1=\pm\sqrt{5}\\\\3x=1\pm\sqrt{5}\\\\x=\frac{1\pm\sqrt{5}}{3}\\ \\\{\frac{1+\sqrt{5}}{3},\:\frac{1-\sqrt{5}}{3}\}$

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2 years ago