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Vsevolod [243]
3 years ago
9

Elements are organized on the periodic table based on their properties. Which statement correctly predicts and explains the chem

ical reactivity of two metals?
A) The alkali metal atom forms a +1 ion, while the alkaline earth metal atom forms a +2 ion.
B) The alkali metal atom forms a +2 ion, while the alkaline earth metal atom forms a +1 ion.
C) The alkali metal atom has one less shell of electrons than the atom of the alkaline earth metal.
D) The alkali metal atom has one more shell of electrons than the atom of the alkaline earth metal.
Chemistry
2 answers:
kari74 [83]3 years ago
8 0

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

Chemical reactivity is defined as the tendency of an atom to loose or gain electrons.

Metals are the elements that looses electrons and thus, their chemical reactivity will be the tendency to loose electrons.

Their chemical reactivity decreases as we move from left to right in a period. This is so because, the electron get added up in the same shell. So, the electron in the outermost orbital gets more tightly bonded to nucleus. And hence, loosing an electron will require high energy. Thus, the chemical reactivity decreases.

  • Alkali metals are the elements which belong to group 1 of the periodic table. The general electronic configuration of these metals is ns^1

These metals will loose 1 electron to form +1 ions.

  • Alkaline earth metals are the elements which belong to group 2 of the periodic table. The general electronic configuration of these metals is ns^2

These metals will loose 2 electrons to form +2 ions.

Hence, the correct answer is Option A.

makkiz [27]3 years ago
6 0
A) The alkali metal atoms forms a +1 ion, while the alkaline eaeth metal atom forms a +2 ion.
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6 At STP, which element is a good conductor of electricity?(1) chlorine (3) silver
alexgriva [62]
For an object to conduct electricity it should have free or delocalised electrons that are free to pass the charge and hence take part in conducting electricity.
From the given choices
Chlorine is a halogen existing as a diatomic gas. Iodine too is a halogen and 2 Iodine atoms held together by covalent bond. Cl - Cl bonds and I-I bonds are  covalent bonds. the outer electrons of Cl and I take part in covalent bonds therefore they are fixed and not free to move about. therefore no free electrons to conduct electricity.
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Silver is a metal and a general property of metals are their ability to conduct electricity.
metal structure are metal ions tightly packed together. when the metal atoms are tightly packed their valence electrons are removed and delocalised. Positively charged metal ions are embedded in a sea of delocalised electrons.
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answer is 3) silver
3 0
3 years ago
Read 2 more answers
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NISA [10]

Answer:

ladidididadaladaddididi

Explanation:

5 0
2 years ago
You have 0.14 moles of sodium chloride (NaCl). How many grams do you have? ( 1 mole of NaCl = 58 grams NaCl) *
Step2247 [10]

Answer:

Option D is correct = 8.12 grams of NaCl

Explanation:

Given data:

Moles of sodium chloride = 0.14 mol

Mass of sodium chloride = ?

Solution:

Formula:

Number of moles = mass of NaCl / Molar mass of NaCl

Molar mass of NaCl = 58 g/mol

Now we will put the values in formula.

0.14 mol = Mass of NaCl / 58 g/mol

Mass of NaCl = 0.14 mol  ×  58 g/mol

Mass of NaCl = 8.12 g of NaCl

Thus, 0.14 moles of NaCl contain 8.12 g of NaCl.

4 0
3 years ago
___ Au₂S₃ + ___ H₂ → ___ Au + ___ H₂S
Natalija [7]

Answer:

2Au₂S₃ +  6H₂ → 4Au + 6H₂S

Explanation:

Balancing:

2Au₂S₃ +  6H₂ → 4Au + 6H₂S

6 0
2 years ago
A cyanide solution with avolume of 12.73 mL was treated with 25.00 mL of Ni2+solution (containing
natima [27]

Answer:

The molarity of this solution is 0,09254M

Explanation:

The concentration of the Ni²⁺ solution is:

Ni²⁺ + EDTA⁴⁻ → Ni(EDTA)²⁻

0,03935L × 0,01307M = 5,143x10⁻⁴ moles Ni²⁺ ÷ 0,03010L =<em>0,01709M Ni²⁺</em>

25,00 mL of this solution contain:

0,01709M × 0,02500L = 4,2716x10⁻⁴ moles of Ni²⁺

The moles of Ni²⁺ that are in excess and react with EDTA⁴⁻ are:

0,01015L × 0,01307M = 1,3266x10⁻⁴ moles of Ni²⁺

Thus, moles of Ni²⁺ that react with CN⁻ are:

4,2716x10⁻⁴ - 1,3266x10⁻⁴ = 2,9450x10⁻⁴ moles of Ni²⁺

For the reaction:

4CN⁻ + Ni²⁺ → Ni(CN)₄²⁻

Four moles of CN⁻ react with 1 mole of Ni²⁺:

2,9450x10⁻⁴ moles of Ni²⁺ × \frac{4 mol CN^-}{1 molNi^{2+}} = <em>1,178x10⁻³ moles of CN⁻</em>

As the volume of cyanide solution is 12,73mL. The molarity of this solution is:

<em>1,178x10⁻³ moles of CN⁻ ÷ 0,01273L = </em><em>0,09254M</em>

I hope it helps!

5 0
2 years ago
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