What is the freezing point of a .743 m aqueous solution of KCl
1 answer:
Change in freezing point = -1.86 C/m X 0.743 m X 2 = -2.76 C
You might be interested in
Density = Mass ÷ Volume
D= 30g ÷ 6 cm^3
D= 5 g/dm^3
Answer:
follow my instagram to help you with your school work in general
Answer:
hearing aid
Explanation:
an artificial body part
is there supposed be a picture with the question?
Answer:
that will be endothermic reaction...... as oxides of mercury decomposes and break s into simpler elements by absorbing energy
Explanation:
hope it helped u buddy