What is the freezing point of a .743 m aqueous solution of KCl
1 answer:
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8.3mL
Explanation:
Given parameters:
Mass of acetone = 6.54g
Density of acetone = 0.7857 g/mL
Unknown:
Volume of acetone = ?
Solution:
Density is defined as the mass per unit volume of a substance. It is expressed mathematically as shown below:
Density =
Since the unknown is volume, we make it the subject of the formula
Volume =
Input the values;
Volume = = 8.3mL
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<u>Answer:</u> The correct answer is Option b.
<u>Explanation:</u>
To calculate the amount of heat absorbed or released, we use the following equation:
.....(1)
where, q = amount of heat absorbed or released.
m = mass of the substance
c = heat capacity of water = 4.186 J/g ° C
= Change in temperature
- <u>For Trial 1:</u>
We are given:
Putting values in equation 1, we get:
q = 5023.2 J
- <u>For trial 2:</u>
We are given:
Putting values in equation 1, we get:
q = 1674.4 J
Heat gained by Trial 1 than trial 2 =
Hence, the amount of heat gained in Trial 1 about 3347 J more than the heat released in Trial 2.
Thus, the correct answer is Option b.