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lorasvet [3.4K]
3 years ago
8

D=ut+5 make u the subject

Chemistry
1 answer:
Levart [38]3 years ago
6 0

Explanation:

d=ut+5

d-5=ut

d-5/t=u

!!!!!!!

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Cl2 + NaBr<br>which two elements will trade places?​
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Why do you think scientist can use the basic properties of matter to help identify an unknown substance?
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NH_{4}Cl and NaCl<br> Balanced Equation<br> Total Ionic Equation<br> Net Ionic Equation
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Answer:

Based on compounds given, NO reaction occurs

Explanation

The compounds should exchange ions to generate a driving force that pulls the reaction to completion. => Example ...

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NH₄Cl(aq) + AgNO₃(aq) => NH₄NO₃(aq) + AgCl(s)

Silver chloride forms in this reaction as a solid precipitate because of its low solubility and is the 'Driving Force' of the reaction. Driving Force is a more stable compound than any on the reactant side and when formed leaves the reaction system as a solid ppt, liquid weak electrolyte (i.e., weak acid or weak base) or a gas decomposition product of a weak electrolyte.

The Ionic Equation is ...

NH₄⁺(aq) + Cl⁻(aq) + Ag⁺(aq) + NO₃⁻(aq) => NH₄⁺(aq) + NO₃⁻(aq) + AgCl(s)

This shows all ions from reaction plus the Driving Force of the reaction.

The Net Ionic Equation is ...

Ag⁺(aq) + Cl⁻(aq) => AgCl(s)

The Net Ionic Equation shows only those ions undergoing reaction. The NH₄⁺ and NO₃⁻ ions are 'Spectator Ions' and do not react.

Attached is a reference sheet for determining the Driving Force of a Metathesis Double Replacement Reaction. Suggest reviewing acid-base theories and the products of decomposition type reactions.

6 0
3 years ago
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Answer:

The answer to the question is

The specific heat capacity of the alloy = 1.77 J/(g·°C)

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To solve this, we list out the given variables thus

Mass of alloy = 45 g

Initial temperature of the alloy = 25 °C

Final temperature of the alloy = 37 °C

Heat absorbed by the alloy = 956 J

Thus we have

ΔH = m·c·(T₂ - T₁) where  ΔH = heat absorbed by the alloy = 956 J, c = specific heat capacity of the alloy and T₁ = Initial temperature of the alloy = 25 °C , T₂ = Final temperature of the alloy = 37 °C  and m = mass of the alloy = 45 g

∴ 956 J = 45 × C × (37 - 25) = 540 g·°C×c  or

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The specific heat capacity of the alloy is 1.77 J/(g·°C)

3 0
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