Answer:
<h2>6.41 %</h2>
Explanation:
The percentage error of a certain measurement can be found by using the formula
From the question
actual density = 7.80 g/cm³
error = 7.30 - 7.80 = 0.5
We have
We have the final answer as
<h3>6.41 %</h3>
Hope this helps you
Answer:
See the answer below
Explanation:
<u>A scientist B might want to replicate the experiment of another scientist A in order to assess the claims made by scientist A.</u> In other words, replication of the experiment of another scientist is done to see if a similar outcome would be arrived at or there would be variations.
<em>The claims made by a scientist while reporting the outcome of a particular experiment must be reproducible by another scientist under similar conditions. Otherwise, the claims are said to be false.</em>
Answer:
Br
|
Br-P-Br
|
Br
Explanation:
To calculate the valance electrons, look at the periodic table to find the valance electrons for each atom and add them together. P is in column 5A, so it has 5, Br is in column 7A, so it has 7 (multiply by 4 since there are 4 Br atoms to give 28) and there is a 1- charge, so add one more electron. 5+28+1=34, so there are 34 electrons to place. P would be the central atom, so place it in the middle. Place each Br around the P (as shown above) with a a single line connecting it. Each line represents 2 electrons, so 8 total have been place, leaving 26 remaining. Place 6 electrons around each Br (2 on each of the unbonded sides), which leaves 2 electrons remaining. The remaining pair of unbound electrons will be attached to the P between any two Br atoms. Phosphorus doesn't have to follow the octet rule, so it actually ends up with 10 valance electrons.
The s orbitals are not symmetrical in shape is a FALSE statement.
An s orbital is so symmetric, more specifically spherically symmetric that it looks the same from all directions.
- The atomic orbitals in the atoms of elements differ in shape.
In essence, the electrons they describe have varying probability distributions around the nucleus. The spherical symmetry of s orbitals is evident in the fact that all orbitals of a given shell in the hydrogen atom have the same energy.
- All s orbitals are spherically symmetrical. Put simply, an electron that occupies an s orbital can be found with the same probability at any orientation (at a distance) from the nucleus.
The s orbitals are therefore represented by a spherical boundary surface which is a surface which captures a high proportion of the electron density.
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brainly.com/question/5087295
Answer: There is one way to write it but i’ll also provide an unbalanced equation and a balanced one.
Explanation:
Unbalanced : Ba (aq) + Cl2 (aq)—-> BaCl (aq)
Balanced : 2Ba (aq) + Cl2 (aq)—> 2BaCl(aq)
