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3 years ago

What term describes a substance that does the dissolving

Chemistry

1 answer:

NARA [144]3 years ago

5 0

A substance that does the dissolving is called a solute.

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Pls help, needed for chemistry

vovangra [49]

Answer:

go to a calculator and see the answer then make the hypothisis which is the answer

Explanation:

magic

7 0

2 years ago

A gas sample occupies a volume of 1 L at 200K. The temperature at which the gas would double its volume is

kicyunya [14]

Answer:

400 K

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

8 0

3 years ago

Which term describes the molecule shown below h-c-c-h ethyne c2h2?

Andru [333]

Ethyne also known as Acetylene and is the simplest Alkyne belonging to Unsaturated Hydrocarbons. It contains triple bond between two carbon atoms in a molecule. Carbon atoms in Acetylene are sp Hybridized and has a linear shape with bond angle of 180° is present between C-C-H bonds. This compound is also called as Binary Compound because it is made up of two elements i.e. Carbon and Hydrogen. The terminal Hydrogen in Acetylene is slightly Acidic in nature, and this compound can donate terminal proton to any strong base. These compounds generally give Electrophillic Addition Reactions.

4 0

3 years ago

Read 2 more answers

What is the volume of 120 mg of water? A. 1.2 dL B. 120 mL C. 120 L D. 1.2 L

mojhsa [17]

I would say B but I am not sure so sorry if it is wrong!!

3 0

3 years ago

Given a gas whose temperature is 418 K at a pressure of 56.0 kPa. What is the pressure of the gas if its Temperature changes to

Rainbow [258]

Answer: P₂=0.44 atm

Explanation:

For this problem, we are dealing with temperature and pressure. We will need to use Gay-Lussac's Law.

Gay-Lussac's Law: $\frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }$

First, let's do some conversions. Anytime we deal with the Ideal Gas Law and the different laws, we need to make sure our temperature is in Kelvins. Since T₂ is 64°C, we must change it to K.

64+273K=337K

Now, it may be uncomfortable to use kPa instead of atm, so let's convert kPa to atm.

$56.0kPa*\frac{1000Pa}{1kPa} *\frac{atm}{101325Pa} =0.55atm$

Since our units are in atm and K, we can use Gay-Lussac's Law to find P₂.

$P_{2} =\frac{T_{2} P_{1} }{T_{1} }$

$P_{2}=\frac{(337K)(0.55atm)}{418K}$

P₂=0.44 atm

8 0

3 years ago