The ratio of the diffusion rate of Cl2 and O2 is 1.5
calculation
rate of diffusion Cl2/ rate of diffusion O2 =√ molar mass of Cl2/ molar mass of O2
molar mass of Cl2 = 35.5 x2 = 71 g/mol
molar mass O2 = 16 x2 =32g/mol
that is rate of diffusion Cl2/ rate of diffusion of O2 =√ 71/ 32= 1.5
We can’t answer this question without any information. There is no explanation of the lab, nor is there any data.
Answer:
P4Se3
Explanation:
Applying the Law of Conservation of Mass:
(133 mg total) - (45.8 mg P) = 87.2 mg Se
Dividing by the molar mass,
Phosphorus:-(45.8 mg P) / (30.97376 g P/mol) = 1.4786 mmol P
Selenium:-(87.2 mg Se) / (78.96 g Se/mol) = 1.1044 mmol Se
Divide by the smaller number of millimoles:
(1.4786 mmol P) / 1.1044 mmol = 1.339
(1.1044 mmol Se) / 1.1044 mmol = 1.000
multiply by 3, to get a whole number interger. then round to the nearest whole numbers to find the empirical formula.
Therefore the empirical formula is P4Se3
Answer:
25,104
Explanation:
100.0 x 4.184 x 60.0 = 25,104
AS given that we have started with a solid powder on a glass plate which appears to be blackish yellow, on passing magnet the black particles separated.
so the black particles are magentic in nature. however the yellow portion of powder is not magnetic or diamagnetic
so its clear that we are able to separate the black and yellow portions by simple physical methods.
If we are able to separate any two substances by simple physical methods then it means that the powder is a mixture and not a compount
