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Arte-miy333 [17]
4 years ago
7

Which of the following is NOT a symbol for an element? H Li Pb HF

Chemistry
2 answers:
sp2606 [1]4 years ago
3 0
HF because an element is always a capital then a lowercase letter
ohaa [14]4 years ago
3 0
HF because an element always has a capital letter first then a lowercase.
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A 5 gram round ball has a density of 1.25 grams/milliliter. What is the volume of the round ball?
Arlecino [84]

Explanation:

m=5g

density=1.25g/ml

density=m/v

v=m/density=5/1.25

4 0
4 years ago
Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =
MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

[O_2]_{eq}=0.587M

K_c=1.35

Putting values in above expression, we get:

1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M

Hence, the equilibrium concentration of water is 0.597 M

8 0
4 years ago
The charge on an ion is known as its___number.
a_sh-v [17]

Answer:

oxidation number is correct!! :)

Explanation:

8 0
3 years ago
Match the financial activities to their relevant management type within the wealth management phase.
alekssr [168]

Answer:

poop

Explanation:

poopy sorry needed points.

4 0
3 years ago
What is missing from the temperature and volume<br> graph shown at right?
Anna11 [10]
X axis hopes this helps
8 0
3 years ago
Read 2 more answers
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