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3 years ago

10

What is it called the number that tells how much of something there is

1 answer:

Dvinal [7]3 years ago

4 0

A cardinal númber is a number that says how many of something there are such a one , two , three , four , five

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When groundwater heated by magma rises to the surface and collects in a natural pool, it is called a

dimaraw [331]

A.hot spring is the right answer.

3 0

3 years ago

Read 2 more answers

A car moving 20 km/h skids 30 m with locked brakes. how far will the car skid with locked breaks if it were traveling at 100 km/

Inessa05 [86]

Kinetic energy = (1/2) (mass) (speed)²

Since the 'speed' in the KE formula is squared, if the car's speed
increases by 5 times, its kinetic energy increases by (5²) = 25 times.

The loss of kinetic energy in a skid is just the wo0rk done by friction
between the tires and pavement. So the skid distance is proportional
to the initial kinetic energy, and the car must skid 25 times as far when
it enters the skid at the higher speed.

25 x 30m = 750 meters

5 0

4 years ago

A foam material has a density of 175 g/l. what is its density in units of lb/ft3?

Oksi-84 [34.3K]

The solution would be like this for this specific problem:

Given: 175 g/L

1 gram/liter = 0.06242796 pound/cubic foot

175 g/L * 0.06242796 pound/cubic foot

= 10.924893 lb/ft3

So, a foam material has a density of 10.924893 lb/ft3 in units of lb/ft3.

4 0

3 years ago

Which diagram correctly represents the electric field lines between two small electrically charged spheres?

hjlf

Answer:

hehe

Explanation:

6 0

3 years ago

In the two-slit experiment, monochromatic light of wavelength 600 nm passes through a 19) pair of slits separated by 2.20 x 10-5

kumpel [21]

Explanation:

It is given that,

Wavelength of monochromatic light, $\lambda=600\ nm=6\times 10^{-7}\ m$

Slits separation, $d=2.2\times 10^{-5}\ m$

(a) We need to find the angle corresponding to the first bright fringe. For bright fringe the equation is given as :

$d\ sin\theta=n\lambda$ , n = 1

$\theta=sin^{-1}(\dfrac{\lambda}{d})$

$\theta=sin^{-1}(\dfrac{6\times 10^{-7}}{2.2\times 10^{-5}})$

$\theta=1.56^{\circ}$

(b) We need to find the angle corresponding to the second dark fringe, n = 1

So, $d\ sin\theta=(n+\dfrac{1}{2})\lambda$

$sin\theta=\dfrac{3\lambda}{2d}$

$\theta=sin^{-1}(\dfrac{3\lambda}{2d})$

$\theta=sin^{-1}(\dfrac{3\times 6\times 10^{-7}}{2\times 2.2\times 10^{-5}})$

$\theta=2.34^{\circ}$

Hence, this is the required solution.

4 0

4 years ago