All categories

3 years ago

Why do electrical devices have resistance

Physics

1 answer:

Kamila [148]3 years ago

8 0

As electrons move through the conductor, some collide with atoms, other electrons, or impurities in the metal.

You might be interested in

A cannon fires a cannonball directly upwards at +150m/s. How long does it take for the cannonball to reach maximum height?

gayaneshka [121]

2 a (x - x0) = (v)^2 - (v0)^2
2(9.80m/s/s)((x - (0)) = (0)^2 - (150.m/s )^2
x = +1150 m
(3 significant digits)

x = +1147.959 m
(More digits if needed)

7 0

2 years ago

A dragster going at 15 m/s increases its velocity to 25 m/s in in 2 seconds. What is its acceleration?

Strike441 [17]

Answer:

5m/s²

Explanation:

Given parameters:

Initial velocity = 15m/s

Final velocity = 25m/s

Time taken = 2s

Unknown:

Acceleration = ?

Solution:

Acceleration is the rate of change of velocity with time taken. It is mathematically expressed as;

Acceleration = $\frac{Final velocity - Initial velocity }{Time taken }$

Acceleration = $\frac{25 - 15}{2}$ = 5m/s²

8 0

3 years ago

Two strings have the same length and tension. One string has a mass per length that is 4 times that of the other string. The fun

Anit [1.1K]

Answer:

$f_1=\frac{f_2}{2}$

Explanation:

the Frequency of string is given by

$f= \frac{1}{2l}\times\sqrt{\frac{T}{\mu }}$

T= tension in the string

μ= mass per unit length of string

l= length of string

in the given question $\mu_{1}$ = 4 $\mu_{2}$

here subscript 1 is massive string and subscript 2 is lighter string

$f_{1}= \frac{1}{2l}\times\sqrt{\frac{T}{\mu_{1} }}$

and

$f_{2}= \frac{1}{2l}\times\sqrt{\frac{T}{\mu_{2} }}$

dividing f_1 by f_2 we get

now $\frac{f_{1}}{f_{2}} =\sqrt{\frac{\mu_2}{\mu_1} }$

= $\sqrt{\frac{\mu_2}{4\mu_2} }$

= $\frac{1}{2}$

⇒ $f_1=\frac{f_2}{2}$

hence the fundamental frequency of massive string is half of the fundamental frequency of lighter string

5 0

3 years ago

Which human activity causes the most erosion?

Ksivusya [100]

Answer:

Explanation:

3 0

3 years ago

A light ray incident from medium 1 to medium 2, where n1>n2. When the incident angle exceed the critical angle ac, the refrac

vovikov84 [41]

Explanation:

(a)

Critical angle is the angle at the angle of refraction is 90°. After the critical angle, no refraction takes place.

Using Snell's law as:

$n_1\times {sin\theta_i}={n_2}\times{sin\theta_r}$

Where,

${\theta_i}$ is the angle of incidence

${\theta_r}$ is the angle of refraction = 90°

${n_2}$ is the refractive index of the refraction medium

${n_1}$ is the refractive index of the incidence medium

Thus,

$n_1\times {sin\ \theta_{critical}}={n_2}\times{sin\ 90^0}$

The formula for the calculation of critical angle is:

${sin\theta_{critical}}=\frac {n_2}{n_1}$

Where,

${\theta_{critical}}$ is the critical angle

(b)

No it cannot occur. It only occur when the light ray bends away from the normal which means that when it travels from denser to rarer medium.

7 0

4 years ago

Why do electrical devices have resistance​

Why do electrical devices have resistance