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2 years ago

HURRY

Physics

1 answer:

motikmotik2 years ago

6 0

Answer:

in the direction opposite to electric field.

Explanation:

Force on a charged particle

due to electric field

is given by

→

−

0.06

200

−

12 N

Here negative indicates that force is in the direction opposite to electric field.

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Answer these please.

PolarNik [594]

Explanation:

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5 0

4 years ago

A hot-air balloon rises from ground level at a constant velocity of 3.0 m/s. One minute after liftoff, a sandbag is dropped acci

tekilochka [14]

Answer:

a) It takes 6,37 s b) The Velocity is -59,43 m/s

Explanation:

The initial variables of the balloon are:

Xo = 0 m

Vo = 3 m/s

After one minute the situation is the following:

t= 60 s

X1 = Xo + Vo*t

X1= 0 m + 3 m/s * 60s

X1= 180m

So when the bag falls, its initial variables are the following:

Xo = 180m

X1 = 0m

Vo = 3 m/s

V1= ?

a= -9,8 m/s2

The ecuation of movement for this situation is:

X = Vo*t + 1/2 a* $t^{2}$

So:

-180m = 3m/s*t+ 1/2*-9,8 m/s2 * $t^{2}$

To solve this we have

a=-9,8/2

b=3

c=180

The formula is: $(-b +/- \sqrt{b^{2} -4ac}) /2a$

Replacing, we get to 2 solutions, where only the positive one is valid because we are talking about time.

<u>So the answer a) is t= 6,37 s</u>

With that answer we can find the question b), with the following movement formula.

Vf = Vo + at

Vf = +3 m/s + (-) 9,8 m/s2 *6,37s

b) Vf = -59,43 m/s

5 0

3 years ago

A bee flies at a constant rate of 5

Volgvan

∆v = -5 m/s
∆t = 5 s

a = ∆v/∆t = (-5 m/s)/(5 s) = -1 m/s^2 .

I know that's the right answer.
I THINK that's what choice-B is trying to say.

4 0

4 years ago

A paintball is fired horizontally from a tower 45 m above the ground. If the paintball gun fires at 90 m/s… How long does it tak

ankoles [38]

Answer:

The time taken for the paint ball to hit the ground is $t = 2.143 \ s$

The distance of the landing point from the tower is $d = 192.86 \ m$

Explanation:

From the question we are told that

The height of the tower is $h = 45 \ m$

The speed of the paintball in the horizontal direction is $v_x = 90 \ m/s$

Generally from kinematic equation we have that

$h = ut + \frac{1}{2} at^2$

Here u is the initial velocity of the paintball in the vertical direction and the value is 0 m/s , this because the ball was fired horizontally

a is equivalent to $g = 9.8\ m/s^2$

t is the time taken for the paintball to hit the ground

$45 = 0* t + \frac{1}{2} 9.8 * t^2$

=> $t = 2.143 \ s$

Generally the distance of its landing position from the tower is

$d = v * t$

=> $d = 90 * 2.143$

=> $d = 192.86 \ m$

3 0

3 years ago

You throw a ball with a speed of 25.0 m/s at an angle of 40.0â—¦ above the horizontal directly toward a wall. The wall is 22.0 m

Alina [70]

The ball takes about 1.15 seconds to reach the wall

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem!

This problem is about Projectile Motion

<u>Given:</u>

initial speed = u = 25 m/s

angle of speed = θ = 40.0°

horizontal distance = x = 22.0 m

<u>Unknown:</u>

time taken by the ball = t = ?

<u>Solution:</u>

<em>We will use this following formula to find the time taken by the ball to reach the wall:</em>

$x = u_x t$

$x = u \cos \theta ~t$

$22 = 25 \cos 40^o ~t$

$t = 22 \div ( 25 \cos 40^o )$

$t \approx 1.15 \texttt { seconds}$

$\texttt{ }$

<h2>Conclusion :</h2>

The ball takes about 1.15 seconds to reach the wall

$\texttt{ }$

<h3>Learn more</h3>

Velocity of Runner : brainly.com/question/3813437
Kinetic Energy : brainly.com/question/692781
Acceleration : brainly.com/question/2283922
The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Projectile , Motion , Horizontal , Vertical , Release , Point , Ball , Wall

7 0

3 years ago

Read 2 more answers