Answer:
16 ft²
Step-by-step explanation:
The complete question is attached.
A trapezoid is a quadrilateral (has four sides) with one a parallel base. The base angles and the diagonals of an isosceles trapezoid are equal.
The area of a trapezoid = [(sum of the parallel bases) / 2] * height of the trapezoid.
Given that the parallel bases are 3 ft and 5 ft, while the height of the trapezoid is 4 ft. Hence:
The area of a trapezoid = [(3 + 5)/2] * 4
The area of a trapezoid = 16 ft²
Answer is C. Rate if correct please
Answer:
ST = 20
Step-by-step explanation:
Line segment RS and segment ST must add up to line segment RT
Step 1: Define
RS = 17
ST = x + 6
RT = 3x - 5
Step 2: Set up equation
mRS + mST = mRT
17 + x + 6 = 3x - 5
Step 3: Solve for <em>x</em>
x + 23 = 3x - 5
23 = 2x - 5
28 = 2x
x = 14
Step 3: Find mST
ST = x + 6
ST = 14 + 6
ST = 20
Jonah is the one that is correct because 1/6th of 1248 is 208. Then you add 1248 and 208 which is 1456 which is the correct answers
Answer:
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
Find the measure of angle KOM
In the triangle KOM
we have
Applying the law of cosines
step 2
Find the measure of the arc KM
we know that
----> by central angle
we have
so
step 3
Find the measure of angle KLM
we know that
The inscribed angle is half that of the arc comprising
![m\angle KLM=\frac{1}{2}[arc\ KM]](https://tex.z-dn.net/?f=m%5Cangle%20KLM%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20KM%5D)
we have
substitute
![m\angle KLM=\frac{1}{2}[106.26^o]](https://tex.z-dn.net/?f=m%5Cangle%20KLM%3D%5Cfrac%7B1%7D%7B2%7D%5B106.26%5Eo%5D)
