Cl is stable as a diatomic molecule where the 2 Cl atoms are held together by a covalent bond
molar mass of the diatomic molecule is 70.9 g/mol
therefore 70.9 g of Cl₂ is - 1 mol
then 140 g of Cl₂ is - 1/70.9 x 140 = 1.97 mol
there are 1.97 mol of Cl₂ present
Answer: B. Ca2+ + 2e- ---------> Ca
Explanation:
Reduction involves the gaining of electrons as well as a decrease in the oxidation state of the atom or ion.
In this case; Ca2+ gains two electrons and the oxidation state is reduced from +2 to 0.
Ca2+ + 2e- ---------> Ca
Answer : The correct option is B (clay, slit, sand).
Explanation :
Soil particles are of three types : Sand, Slit and clay. Most of the soils particles are made up of a combination of sand, slit and clay.
Particle size range of the sand = 2.00 -0.05 mm
Particle size range of the slit = 0.05 -0.002 mm
Particle size range of the sand = less than 0.002 mm
Sand is the largest soil particle, clay is the smallest soil particle and slit particle is present in between the sand & clay particle.
Therefore, the order from smaller to larger sediment particles is
Clay > Slit > Sand
Answer:
No se pues carnal preguntale a alguien mas.
Explanation:
lo siento:(
Molar mass ( CuSO₄) = 159.609 g/mol
159.609 g ----------------- 6.02 x 10²³ molecules
? g ------------------ 3.36 x 10²³ molecules
mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³
mass = 5.36 x 10²⁴ / 6.02 x 10²³
mass = 8.90 g
hope this helps!
