Is tap water a mixture or a pure substance

2 answers:

8 0

Mixture. Distilled Water may be a pure substance, however, there are many minerals and such that are in tap water, making it a mixture.

Sergeu [11.5K]4 years ago

5 0

I think its pure because tap waters does have not any or contains harmful substances. Its depend on your place

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if you have five grams of product after a chemical reaction,how many grams of ractants did you have at the start of the reaction

Kitty [74]

Due to the law of conservation of mass, you will end up with the same as what you started with. So in this case, five grams.

4 0

3 years ago

An aqueous solution of nitric acid is standardized by titration with a 0.110 M solution of calcium hydroxide. If 21.1 mL of base

Mumz [18]

Answer:

$\large \boxed{\text{0.195 mol/L}}$

Explanation:

(a) Balanced equation

2HNO₃ + Ca(OH)₂ ⟶ Ca(NO₃)₂ + 2H₂O

(b) Moles of Ca(OH)₂

$\text{Moles of Ca(OH)}_{2} = \text{21.1 mL Ca(OH)}_{2} \times \dfrac{\text{0.110 mmol Ca(OH)}_{2}}{\text{1 mL Ca(OH)}_{2}}\\= \text{2.321 mmol Ca(OH)}_{2}$

(c) Moles of HNO₃

The molar ratio is 2 mol HNO₃:1 mol Ca(OH)₂

$\text{Moles of HNO}_{3} = \text{2.321 mmol Ca(OH)}_{2} \times\dfrac{\text{2 mmol HNO}_{3}}{\text{1 mmol Ca(OH)}_{2}}= \text{4.642 mmol HNO}_{3}$

(d) Molar concentration of HNO₃

$c = \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\c = \dfrac{n}{V}\\\\c= \dfrac{\text{4.642 mmol}}{\text{23.8 mL}} = \text{0.195 mol$\cdot$L$^{-1}$}\\\\\text{The molar concentration of the Ca(OH)$_{2}$ is $\large \boxed{\textbf{0.195 mol/L}}$}$