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ZanzabumX [31]
3 years ago
6

The main function of concept mapping is:

Chemistry
1 answer:
SSSSS [86.1K]3 years ago
5 0
D. Simplification incorrect answer
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Which characteristics define a liquid?
Nadya [2.5K]

Hello I am absolutely positve the answer is D. Mark brainliest :)

8 0
3 years ago
Read 2 more answers
If 0.600mol of chloride gas reacted with 0.500mol of aluminium metal to produce aluminium chloride,which reactant is in excess?h
alisha [4.7K]

Answer:

собак гандонов в гавне))))))))))

Explanation:

hloride,which reactant is in excess?how many moles of aluminium chloride can be produced during the reaction.hloride,which reactant is in excess?how many moles of aluсиськижопыссиськасуксиськипись loride can be produced during the reaction.hloride,which reactant is in excess?how many moles of aluminium chloride can be produced during the reaction.hloride,whichйух reactant is in excess?how many moles of aluminium chloride can be produced during the reaction.

5 0
3 years ago
Please help me with this question
yKpoI14uk [10]

The mass of oxygen is 236.4 g.

Explanation:

To find the mass of oxygen in 325 g of carbon dioxide (CO₂) we follow the next algorithm.

First we calculate the molar weight of carbon dioxide:

molar weight of CO₂ = molar weight of carbon × 1 + molar weight of oxygen × 2

molar weight of CO₂ = 12 × 1 + 16 × 2 = 44 g/mole

Now we devise the following reasoning:

if in        44 g of CO₂ there are 32 g of oxygen

then in  325 g of CO₂ there are X g of oxygen

X = (32 × 325) / 44 = 236.4 g oxygen

Learn more about:

molar weight

brainly.com/question/9883301

#learnwithBrainly

6 0
3 years ago
Which layer of earth atmosphere contains no water vapor, has an atmospheric pressure less than 0.1 atmosphere, and has an air te
JulijaS [17]
Well could u list the layers for me? It would be helpful to answer
8 0
4 years ago
Calculate the mass of water produced when 7.26 g of butane reacts with excess oxygen
MaRussiya [10]

Answer:

11.3 g.

Explanation:

Hello there!

In this case, since the combustion of butane is:

C_4H_{10}+\frac{13}{2} O_2\rightarrow 4CO_2+5H_2O

Thus, since there is a 1:5 mole ratio between butane and water, we obtain the following mass of water:

m_{H_2O}=7.26gC_4H_{10}*\frac{1molC_4H_{10}}{58.14gC_4H_{10}}*\frac{5molH_2O}{1molC_4H_{10}}  *\frac{18.02gH_2O}{1molH_2O}

Therefore, the resulting mass of water is:

m_{H_2O}=11.3gH_2O

Best regards!

4 0
3 years ago
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