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Answer:
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Explanation:
hloride,which reactant is in excess?how many moles of aluminium chloride can be produced during the reaction.hloride,which reactant is in excess?how many moles of aluсиськижопыссиськасуксиськипись loride can be produced during the reaction.hloride,which reactant is in excess?how many moles of aluminium chloride can be produced during the reaction.hloride,whichйух reactant is in excess?how many moles of aluminium chloride can be produced during the reaction.
The mass of oxygen is 236.4 g.
Explanation:
To find the mass of oxygen in 325 g of carbon dioxide (CO₂) we follow the next algorithm.
First we calculate the molar weight of carbon dioxide:
molar weight of CO₂ = molar weight of carbon × 1 + molar weight of oxygen × 2
molar weight of CO₂ = 12 × 1 + 16 × 2 = 44 g/mole
Now we devise the following reasoning:
if in 44 g of CO₂ there are 32 g of oxygen
then in 325 g of CO₂ there are X g of oxygen
X = (32 × 325) / 44 = 236.4 g oxygen
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Answer:
11.3 g.
Explanation:
Hello there!
In this case, since the combustion of butane is:

Thus, since there is a 1:5 mole ratio between butane and water, we obtain the following mass of water:

Therefore, the resulting mass of water is:

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