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BlackZzzverrR [31]
3 years ago
14

What is the name of the compound?

Chemistry
1 answer:
Andrei [34K]3 years ago
5 0
<h2><u>Trichlorofluoromethane</u></h2><h2><u /></h2>
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An atom of sodium and an atom of flourine will combine to form sodium flouride. Which of the following correctly describes sodiu
Alenkasestr [34]

Answer:

A compound

Explanation:

A compound is formed when two elements combine together. Both sodium and fluorine are elements. These elements combine via the process of chemical bonding.

In this case, an ionic bond is formed between sodium and fluorine, this leads to the emergence of the compound sodium chloride, hence the answer above.

4 0
3 years ago
How often do girls normally experience menstruation a.once every 30 days b. once every 29 c.once every 28 d.once every 27
kramer

Answer:

i think answer is a, every 30 days

5 0
3 years ago
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2. Draw a structural formula for 3,4-hexene (C6H12), which has a double bond between the number 3 and 4 carbons in the chain. Wh
Rufina [12.5K]
The structure will be:
H₃C-CH₂-CH=CH-CH₂-CH₃
This class of compounds is known or referred to as alkenes. Alkenes are unsaturated hydrocarbons that contain a carbon-carbon double bond. The present of this double bond alters the properties of alkenes rom alkanes.
8 0
3 years ago
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2. Nitrogen has two naturally occurring
kvv77 [185]

Answer:

Suppose that:

Mass of N-14= 14

and Mass of N-15= 15

fraction N-14 x 14 + fraction N-15 x 15 = 14.007

now.. if the fractions were =, that is if fraction N-14 = fraction N-15 = 0.5, then...

0.5 x 14 + 0.5 x 15 = 14.5

more N-15 would make that number larger...

0.3 x 14 + 0.7 x 15 = 14.7

let x = abundance of N-14, then (1-x) = abundance of N-15, and we could solve for x.

(X)x14 + (1-X)x 15 = 14.007

14X + 15 - 15X = 14.007

X = 0.993

the relative abundance of N-14 = 99.3%

the relative abundance of N-15 = 0.7%

So, according to the above explanation N-14 is abundant

Explanation:

Suppose that:

Mass of N-14= 14

and Mass of N-15= 15

fraction N-14 x 14 + fraction N-15 x 15 = 14.007

now.. if the fractions were =, that is if fraction N-14 = fraction N-15 = 0.5, then...

0.5 x 14 + 0.5 x 15 = 14.5

more N-15 would make that number larger...

0.3 x 14 + 0.7 x 15 = 14.7

let x = abundance of N-14, then (1-x) = abundance of N-15, and we could solve for x.

(X)x14 + (1-X)x 15 = 14.007

14X + 15 - 15X = 14.007

X = 0.993

the relative abundance of N-14 = 99.3%

the relative abundance of N-15 = 0.7%

So, according to the above explanation N-14 is abundant

8 0
3 years ago
Which element is placed in the same period as ruthenium but has a higher atomic number than it?
emmasim [6.3K]

Answer:

The part that is put in the same time as ruthenium, but has a greater number of atoms than silver.

8 0
3 years ago
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