Answer:
Explanation:
There are a couple of assumptions I had to make here and also a couple of rules based on what I use in my classroom when I teach the Law of Momentum Conservation. First of all, I am going to call the 8kg ball 1 and say that it is moving to the right (and right is positive), and that means that the 3kg ball is ball 2 and say that it is moving to the left (and left is negative). I had to assume that the 2 balls were moving towards each other; hence, the different signs assigned to their movement. I also added in another significant digit since we have only 1 in most of these values and adding in a .0 is not going to change the value of any number. The Law of Momentum Conservation in this particular instance says
which is the mathematical way of saying that the momentum after the collision is the same as the momentum before it. Filling in:
and doing the math here simplifies to
32 - 42 = -16 + 3.0v and
-10 = -16 + 3.0v and
6.0 = 3.0v so
v = 2.0 (and the positive indicates that ball 2 is now moving to the right)
Answer:
D = 26.97 m
Explanation:
given,
you walk 12.5 m in a direction exactly 19° south of west
after that 19.5 m in a direction exactly 39° west of north.
distance calculation from the starting point = ?
D₁ = d₁ cos θ
D₁ = 12.5 x cos 19°
D₁ = 11.82 m
D₂ = d₂ cos θ
D₂ = 19.5 x cos 39°
D₂ = 15.15 m
distance from the starting point
D = D₁ + D₂
D = 11.82 + 15.15
D = 26.97 m
Distance from the starting point is equal to 26.97 m
Answer:
You should multiply 60 kg*9.8 and answer will come.
Hope this will help you.
Answer:
Lastly, the heat transfer rate depends on the material properties described by the coefficient of thermal conductivity. All four factors are included in a simple equation that was deduced from and is confirmed by experiments. The rate of conductive heat transfer through a slab of material, such as the one in Figure 3, is given by
Q
t
=
k
A
(
T
2
−
T
1
)
d
,
where
Q
t
is the rate of heat transfer in watts or kilocalories per second, k is the thermal conductivity of the material, A and d are its surface area and thickness, as shown in Figure 3, and (T2 − T1) is the temperature difference across the slab. Table 1 gives representative values of thermal conductivity.
Explanation:
If a source generates an electric field of 1236 N/C at a distance of 4 m, the magnitude of the source charge is: A) 2.2 µC