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Gnesinka [82]
3 years ago
14

What are the upper boundaries of each layer of the atmosphere

Physics
1 answer:
kodGreya [7K]3 years ago
6 0
The atmosphere is composed of 5 layers which is 500 kilometers above the ground. This are Troposphere, Stratosphere, Mesoshpere, Thermosphere, and Exosphere. After the Exosphere is the outer bounderies which is the space
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what factors go into decisions about changing what materials should be used when building a products​
Dmitry_Shevchenko [17]

Answer:

you need to consider the use for the product, how brittle the materials are, how they react to certain things, the cost of the materials, the durability and flexibility of the materials, and how easy to obtain the materials are as well as how they would work and how they would hold

6 0
3 years ago
Alexis walked 1.5 km to her house in 0.5 hours. What is Alexis’ speed?
katrin2010 [14]

Answer:

Speed = 3 [km/h]

Explanation:

To solve this problem we must use the definition of speed which relates the distance traveled for a while.

Distance = 1.5 [km] = 1500 [m].

time = 0.5 [hr] = 1800 [s]

Speed = Distance/time

Speed = 1.5/0.5

Speed = 3 [km/h] or 1500/1800 = 0.8333[m/s]

4 0
2 years ago
A car of mass 1500 kg is negotiating a flat circular curve of radius 50 m with a speed of 20 m/s.
Lilit [14]

Answer:

Explanation:

a. The source of centripetal force on the car is  (3) the static friction force.

b. ac = v²/R = (20²)/50 = 8 m/s²

c.  Fc = m(ac) = 1500(8) = 12 kN

d. μ = Fc/N = Fc/mg = 12000 / 1500(9.8) = 0.8163... ≈ 0.82

6 0
3 years ago
A 16 N force is applied to an object and 96 J of work is done. How far was the object moved?
ipn [44]
Your answer would be A. You divide 96 by 16 to find the answer
3 0
3 years ago
Read 2 more answers
A transformer is to be used to provide power for a computer disk drive that needs 6.0 V (rms) instead of the 120 V (rms) from th
Ipatiy [6.2K]

Answer:

N_{2}=20 turns

Explanation:

The given case is a step down transformer as we need to reduce 120 V to 6 V.

number of turns on primary coil N_{P}= 400

current delivered by  secondary coil  I_{S}= 500 mA

output voltage = 6 V (rms)

we know that

I_{p}=\frac{V_{out}}{V_{in}\times I_{s}}

putting values we get

I_{p}=\frac{6}{120\times 0.5}

I_{p}= 0.1 A

to calculate number of turns in secondary

\frac{N_{2}}{400} =\frac{6}{120}

therefore, N_{2}=20 turns

5 0
3 years ago
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