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Gnesinka [82]
3 years ago
14

What are the upper boundaries of each layer of the atmosphere

Physics
1 answer:
kodGreya [7K]3 years ago
6 0
The atmosphere is composed of 5 layers which is 500 kilometers above the ground. This are Troposphere, Stratosphere, Mesoshpere, Thermosphere, and Exosphere. After the Exosphere is the outer bounderies which is the space
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Two sealed 1 l containers full of gas are at room temperature. Container a has a pressure of 4 atm and container b has a pressur
loris [4]

Answer:

The number density of the gas in container A is twice the number density of the gas in container B.

Explanation:

Here we have

P·V =n·R·T

n = P·V/(RT)

Therefore since V₁ = V₂ and T₁ = T₂

n₁ = P₁V₁/(RT₁)

n₂ = P₂V₂/(RT₂)

P₁ = 4 atm

P₂ = 2 atm

n₁ = 4V₁/(RT₁)

n₂ =2·V₁/(RT₁)

∴ n₁ = 2 × n₂

Therefore, the number of moles in container A is two times that in container B and the number density of the gas in container A is two times the number density in container B.

This can be shown based on the fact that the pressure  of the container is due to the collision of the gas molecules on the walls of the container, with a kinetic energy that is dependent on temperature and mass, and since the temperature is constant, then the mass of container B is twice that of A and therefore, the number density of container A is twice that of B.

5 0
3 years ago
A ray of light bends upon entering a new medium. What is this phenomenon called?
Ainat [17]
Refraction is a phenomenon which results when a ray of light enters from one medium to another medium. When a ray of light enters from denser medium to rarer medium, it bends away from the normal. The laws of refraction are: The incident ray, the refracted ray and the normal all lie in the same plane.
3 0
3 years ago
All objects _<br> energy.
Alekssandra [29.7K]

Answer:

Explanation:

All objects <u>radiate</u> energy.

8 0
2 years ago
Convert 1erg into joule by dimensional method​
Valentin [98]

Answer:

1 * 10^-7 [J]

Explanation:

To solve this problem we must use dimensional analysis.

1 ergos [erg] is equal to 1 * 10^-7 Joules [J]

1[erg]*\frac{1*10^{-7} }{1}*[\frac{J}{erg} ] \\= 1*10^{-7}[J]

4 0
2 years ago
For work to be done on the object the object has to
Nata [24]
Gain energy

good luck!
3 0
3 years ago
Read 2 more answers
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