Question

A source charge generates an electric field of 1236 N/C at a distance of 4 m. What is the magnitude of the source charge?

Answer 1

We know that the relationship between Electric Field , Charge  and Distance is given by :

$E=\frac {kQ}{R^2}$

Where, k$=$ Columb's Constant $=8.99\times 10^9 Nm^2C^-2$

Q= Source charge that generates the electric field

R = Distance from the charge =4m

E=Electric field = 1236N/C

As, we have to find the charge therefore rearranging the formula we get :

$Q=\frac {ER^2}{k}$

Putting the values we get

$Q = \frac {1236\times 4^2}{8.99\times 10^9}$

On solving

$Q = \frac {2199.77}{10^9} =2.19 \times 10^-6 =2.2$ µC

Therefore the magnitude of source charge is 2.2 µC  

Answer 2

If a source generates an electric field of 1236 N/C at a distance of 4 m, the magnitude of the source charge is: A) 2.2 µC