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Sati [7]
4 years ago
13

Y = (x - 1) to the second power + 2

Mathematics
1 answer:
Nikolay [14]4 years ago
5 0
Y = (x - 1)² + 2
y = (x² - x - x + 1) + 2
y = (x² - 2x + 1) + 2
y = x² - 2x + (1 + 2)
y = x² - 2x + 3
x² - 2x + 3 = 0
x = <u>-(-2) +/- √((-2)²  4(1)(3))</u>
                     2(1)
x = <u>2 +/- √(4 + 12)</u>
                2
x = <u>2 +/- √(16)
</u>             2<u>
</u>x = <u>2 +/- 4
</u>           2<u>
</u>x = 1 <u>+</u> 2
x = 1 + 2      x = 1 - 2
x = 3            x = -1
y = x² - 2x + 3
y = (3)² - 2(3) + 3
y = 9 - 6 + 3
y = 3 + 3
y = 6
(x, y) = (3, 6)
or
y = x² - 2x + 3
y = (-2)² - 2(-1) + 3
y = 4 + 2 + 3
y = 6 + 3
y = 9
(x, y) = (-1, 9)
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The manager of a company uses the function shown to model the company’s daily profit based on the price of a product in dollars,
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Answer: 1) The minimum price, in dollars, to avoid a loss = 22,

2) the maximum price in dollars , to avoid a loss = 53,

3) The price that results the maximum profit = 37.5 dollars

Step-by-step explanation:

Since the given function that shows the total profit,

f(x) = (x-22)(53-x)

Where x is the price of the product.

Since for avoiding the loss,

f(x) \geq 0,

⇒ (x-22)(53-x)\geq 0

If (x-22)\geq 0 \implies x\geq 22

If 53 - x \geq 0 \implies 53 \geq x

Thus, 53 ≥ x ≥ 22,

Therefore, the minimum price to avoid the loss = $ 22

And, the minimum price to avoid the loss = $ 53

f'(x) =\frac{d}{dx}[(x-22)(53-x)] = (x-22)\frac{d}{dx} (53-x)+(53-x) \frac{d}{dx}(x-22)

⇒ f'(x) = - (x-22)+(53-x) = -x+22+53-x =-2x+75

Now, For maximum or minimum,

f'(x) = 0,

⇒ -2x+75 = 0

⇒ -2x = -75

⇒ x = 37.5

f''(x) = \frac{d}{dx}(-2x+75)=-1

For x = 37.5, f''(x) is negative,

Thus, For the price of $ 37.5 dollars the company has the greatest profit.



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