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Sati [7]
3 years ago
13

Y = (x - 1) to the second power + 2

Mathematics
1 answer:
Nikolay [14]3 years ago
5 0
Y = (x - 1)² + 2
y = (x² - x - x + 1) + 2
y = (x² - 2x + 1) + 2
y = x² - 2x + (1 + 2)
y = x² - 2x + 3
x² - 2x + 3 = 0
x = <u>-(-2) +/- √((-2)²  4(1)(3))</u>
                     2(1)
x = <u>2 +/- √(4 + 12)</u>
                2
x = <u>2 +/- √(16)
</u>             2<u>
</u>x = <u>2 +/- 4
</u>           2<u>
</u>x = 1 <u>+</u> 2
x = 1 + 2      x = 1 - 2
x = 3            x = -1
y = x² - 2x + 3
y = (3)² - 2(3) + 3
y = 9 - 6 + 3
y = 3 + 3
y = 6
(x, y) = (3, 6)
or
y = x² - 2x + 3
y = (-2)² - 2(-1) + 3
y = 4 + 2 + 3
y = 6 + 3
y = 9
(x, y) = (-1, 9)
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dezoksy [38]
<span>The urn contains 2 purple balls and 4 white balls. The player pay $4 for start the game and get $1.5 for every ball drawn until one purple ball is drawn. The maximal revenue would be $7.5 when 4 white balls and 1 purple balls are drawn.
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<span>1. Write down the probability distribution for the player earning

The player earning </span>for each event depends on the number of balls drawn subtracted the ticket price.<span>
p= 2/6
The player earnings would be: 1*$1.5 -$4= - $2.5
wp= (4*2)/(6*5) = 4/15
</span>The player earnings would be: 2*1.5- $4= - $1
wwp= (4*3*2)/(6*5*4)= 1/5
The player earnings would be: 3*$1.5 -$4= $0.5
wwwp= (4*3*2*2)/(6*5*4*3*2)= 2/15 
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wwwwp= (4*3*2*2*1)/(6*5*4*3*2*1) = 1/15
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2. Find its expected value

The expected value would be:
chance of event * earning 
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Total expected value= (1/3 * - 2.5)+ (4/15*-1) + (1/5*0.5) + (2/15 *2) + ( 1/15 *3.5)= 
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Answer:

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Step-by-step explanation:

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The growth rate = 1.05%

Now find the population after 2100. Use the below formula to find the population.

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Now, find the growth rate in 2100.

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Now divide both sides by K, now x = N/K then do the differential equation.

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